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Mathematics 10 Online
OpenStudy (anonymous):

A company has 200 machines. Each machine has 12% probability of not working. If you were to pick 40 machines randomly, the probability that 5 would not be working is

OpenStudy (anonymous):

the probability that all would be working is , and the probability that at least one machine would be working is

OpenStudy (anonymous):

@mathmale @mathmath333 @math_man21

OpenStudy (agent0smith):

Use binomial probability. I assume you have the formula. p=0.12 n=40 k=5

OpenStudy (anonymous):

i do not @agent0smith

OpenStudy (agent0smith):

Google it then, binomial probability formula

OpenStudy (anonymous):

is this what you mean

OpenStudy (anonymous):

n = number of trials k = number of successes n – k = number of failures p = probability of success in one trial q = 1 – p = probability of failure in one trial

OpenStudy (anonymous):

@agent0smith

OpenStudy (agent0smith):

Yes but that isn't the formula.

OpenStudy (anonymous):

what would i be looking for

OpenStudy (agent0smith):

The formula. It comes up in the very first result if you search what I said.

OpenStudy (anonymous):

OpenStudy (agent0smith):

Yes, so... use it.

OpenStudy (anonymous):

man i cant read that

OpenStudy (anonymous):

2.8366108223120563e-7n @agent0smith

OpenStudy (anonymous):

rounded to the thousandth place its 0

OpenStudy (agent0smith):

That's probably not correct. You showed no work, so I have no idea how you arrived at that answer.

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