A company has 200 machines. Each machine has 12% probability of not working.
If you were to pick 40 machines randomly, the probability that 5 would not be working is
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OpenStudy (anonymous):
the probability that all would be working is
, and the probability that at least one machine would be working is
OpenStudy (anonymous):
@mathmale @mathmath333 @math_man21
OpenStudy (agent0smith):
Use binomial probability. I assume you have the formula.
p=0.12
n=40
k=5
OpenStudy (anonymous):
i do not @agent0smith
OpenStudy (agent0smith):
Google it then, binomial probability formula
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OpenStudy (anonymous):
is this what you mean
OpenStudy (anonymous):
n = number of trials
k = number of successes
n – k = number of failures
p = probability of success in one trial
q = 1 – p = probability of failure in one trial
OpenStudy (anonymous):
@agent0smith
OpenStudy (agent0smith):
Yes but that isn't the formula.
OpenStudy (anonymous):
what would i be looking for
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OpenStudy (agent0smith):
The formula. It comes up in the very first result if you search what I said.
OpenStudy (anonymous):
OpenStudy (agent0smith):
Yes, so... use it.
OpenStudy (anonymous):
man i cant read that
OpenStudy (anonymous):
2.8366108223120563e-7n @agent0smith
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OpenStudy (anonymous):
rounded to the thousandth place its 0
OpenStudy (agent0smith):
That's probably not correct.
You showed no work, so I have no idea how you arrived at that answer.