A sum of 7700 is to be divided among three brothers zain, zaid and zohaib in such a away that simple interest on each part at 5% per annum after 1, 2 and 3 years, respectively remains equal. The share of zain is more than that of zohaib by: a) 2800 b) 2500 c) 3000
@KamiBug
This question is more complicated than I thought it would be. Trying to come up with an equation. How do you think we should start?
As far as i think the equation could be like this one, Let x,y and z be the amounts the have, so 0.05x=(2).05y=(3)0.05z
I'm think I see what you are doing A = X e^rt r =0.05 t = 1 Interest = X -A A = Y e^rt r =0.05 t = 2 Interest = Y -A A = Z e^rt r =0.05 t = 3 Interest = Z -A the interest is the same for each brother
Yes but what next??
Maybe setting the first and last equations (we don't care about the middle brother) interest equal to each other and solve for X or Z. I need to work it out on paper to be sure.
Sorry I am not seeing this solution. I need to walk away and think about it some more, maybe the solution will come to me.
Okay. If you get to the solution do tell me.
You do have to factor in the third brother, in order to get the amount correct.
And how are we gonna do that?
@rebeccaxhawaii
Okay. I used an alternate method to solve the problem, in order to give me some insight to how the equation might work. I used excel, created the simple interest equations for the three brothers for various values that summed to 7700. And zeroed in the the accrued interests until the differences were less than a penny or so. It is a not good math, but as an retired engineer, it solves the question. I will attach a picture of the excel, if you don't want to see the answer. Don't look.
@TrojanPoem
Could not use this method to solve this. But thanks anyways for all the help
@retirEEd hey I tried to PM you but you have everyone blocked. I was wondering if you could help me with my problem
HEY I think I solved the equation! Working on the final answer, now. Want to verify before I post it. If I'm right, we were very close and I apologize for not seeing it sooner.
The first thought was incorrect, an error in logic However a revision worked perfectly.... I see you are offline but I will post anyways (Interest originally incorrect I had X - A, Y - A and Z - A) A A = X e^0.05 Interest = A - X so I = X e^0.05 - X I = X (e^0.05 - 1) A = Y e^0.1 Interest = A - Y so I = Y e^0.1 - Y I = Y (e^0.1 - 1) A = Z e^0.15 Interest = A - Z so I = Z e^0.15 - Z I = Z (e^0.15 - 1) ALL of the I s are equal and X + Y + Z = 7700 Solve the first two Is for Y and the first and third I for Z Y = X (e^0.05 - 1) / (e^0.1 - 1) Z = X (e^0.05 - 1) / (e^0.15 - 1) Plug into X + Y + Z = 7700 7700 = X + X (e^0.05 - 1) / (e^0.1 - 1) + X (e^0.05 - 1) / (e^0.15 - 1) 7700 = X [ 1 + (e^0.05 - 1) / (e^0.1 - 1) + (e^0.05 - 1) / (e^0.15 - 1)] Solve for X = 7700 / [ 1 + (e^0.05 - 1) / (e^0.1 - 1) + (e^0.05 - 1) / (e^0.15 - 1)] = 7700 / 1.804315007 (the key punching get hairy) = 4267.547 which is fairly close to my excel answer Follow a similar process to get Z (the third brother) obviously the difference is X -Z
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