MEDAL AND FAN!!!!! PLEASE HELP!!!!!
what do you need help with
It's up above
cant see the whole thing
ok hold on
Ashley paddle from one shore of a lake six miles wide at 8 mph, and Claire paddles from the opposite shore at 10 mph
How long will the travel before they meet?
ok
solving.....
Can you give me an equation or something to use to figure it out
distance = rate x time or d = r*t
So is the equation 6=8x?
Can you explain it to me? Or give me the equation with the numbers in it please?
sorry im trying to figure it out myself havent done this stuff in a long time
It's okay :) Take your time
you still need help?
yes please
ok let me first finish off with someone else first and then Ill come here ^^
Ok thx
Well we will use \(\Large{D=r\times t}\) where D is \(\large{6}\)....we know the speeds that they both are traveling which is \(\large{8mph}\) and \(\large{10mph}\) but we dont know the time between them both so our equation is... \(\Large{8T+10T=6miles}\) in which we add like terms... \(\Large{18T=6miles}\) we now would divide by 18 on both sides...
So divide 6 by 18?
Yup^^ are there answer choices for this?
So tbh this isn't the actual equation..... Sorry... I wanted to change it up so that I could solve the same type of problem twice to make sure I understood it. In the real equation the lake is miles wide and the speed are 4 and 5 mph.
but yes there are answer choices to it
may i see them?
A. 1 hour, 24 minutes B. 27minutes C. 3 hours D. 20 minutes
So I assuming the the equation is 9T=3 miles
So the answer is C right? 3 hours
Not really your equation is correct but the quotient is incorrect you would divide 3 by 9...\(\Large{\frac{3}{9}}\)...then you would multiply the simplified fraction by 60 to get how many minutes it took.....
So then it's 20 minutes?
Yup ^^
thanks
\(\Huge\cal\rlap{\color{red}{No~Problem!:)}}{\color{blue}{\;No~Problem!:)}}\) \(\Huge\cal\rlap{\color{orange}{You~did~A~Great~Job!:)}}{\color{blue}{\;You~did~A~Great~Job!:)}}\)
haha, thanks for showing me the choices:/
sorry :(
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