Question

quetsion

Answer 1

V1= kw^2

for the largest piece after the breakage

V2= k(0.6w)^2

Answer 2

My best tackle on it....

The variation is:
\(\color{#000000}{ \displaystyle {\rm V}=k {\rm W^2} }\)

So, the weight of the value of the two pieces is:
\(\color{#000000}{ \displaystyle k \left(\frac{3}{5}\right)^2+k \left(\frac{2}{5}\right)^2 = \frac{9k}{25}+\frac{4k}{25} = \frac{13k}{25} }\)

When compared to
\(\color{#000000}{ \displaystyle k \left(1\right)^2=k }\)

Answer 3

So, you now only have 13/25's of the value.
That is, you lose 12/25's (or 48/100's) of the value.

So the percentage loss is not difficult.

Answer 4

That third line should say: \(\rm So~the~value,~of~the~two~pieces~is\)

Answer 5

is the answer 52\(\%\)

Answer 6

is the answer 48%

Answer 7

I assume that «percentage loss», means the percent (of the initial value) that is lost (from this initial value).

Answer 8

48 ?

Answer 9

Yes, I believe so. % 48

Answer 10

(13-12)/25*100=48

Answer 11

(25-13)/25*100=48

Answer 12

:)

Answer 13

HAHA