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A solution is made by mixing 43.0 mL of ethanol, C2H6O, and 57.0 mL of water. Assuming ideal behavior, what is the VAPOR pressure of the solution at 20 °C?
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Use Raoult's Law
I tried but I just can't seem to get the right answer
@aaronq
wanna post what you did?
@aaronq
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@aaronq
Okay thats great. now that you have the moles, find the mole fractions \(\sf \chi _A=\dfrac{moles~of~A}{total~moles}\)
I got the mole fraction of ethanol to be 0.189 and the mole fraction of water to be 0.811 @aaronq
k perfect! Now you need to multiply them by the vapour pressures of the pure solvents
Got the answer!! thank you so much for your help !!! @aaronq
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no problem! glad i could help
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Use Hvap of water = 40.7 kJ/mol, c of water = 4.184 J/g.u00b0C, and molar mass of HO = 18.
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