So it's asking how much larger the other ball is.... From what I can tell you only calculated one ball.... Maybe I'm misunderstanding the question but I would think that you would calculate the other ball next with the same equation.....
OpenStudy (anonymous):
\[v=\frac{ 4 }{ 3 }(3.14)(12^{3 })\]
OpenStudy (anonymous):
solve that please
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OpenStudy (isuckatschool43):
7234.56
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
so try this next....
OpenStudy (anonymous):
\[24,416.64-7,234.56\]
OpenStudy (isuckatschool43):
17,182.08
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OpenStudy (anonymous):
I'm pretty sure that is the answer.
OpenStudy (isuckatschool43):
ok. i have a few more if you have time
OpenStudy (anonymous):
yes i think you got it right
OpenStudy (anonymous):
Ok just tag me whenever you need me
OpenStudy (anonymous):
i did do you know history?
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OpenStudy (isuckatschool43):
should i open a new question or just post it here
OpenStudy (anonymous):
new question
OpenStudy (anonymous):
it doesn't matter. it's up to you
OpenStudy (isuckatschool43):
ok
OpenStudy (isuckatschool43):
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OpenStudy (isuckatschool43):
im also thinking 150.72...
OpenStudy (anonymous):
give me a sec
OpenStudy (isuckatschool43):
ok
OpenStudy (anonymous):
Ok so I think that you would start by using the following formula
OpenStudy (anonymous):
\[v =3.14(4^{2})12\]
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OpenStudy (anonymous):
basically it's v=3.14(r^2)h
OpenStudy (anonymous):
dang what grade are youll in thats too confussing?
OpenStudy (anonymous):
I'm a junior... @s10539609
Sorry let me know if I confuse you @isuckatschool43
OpenStudy (anonymous):
type in calculate a cylinder on google
then put 4 for the radius and 12 for the height
OpenStudy (isuckatschool43):
603.19
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OpenStudy (anonymous):
@imqwerty @zepdrix
OpenStudy (anonymous):
Okay good now you need to find the volume of the spheres of ice:
The diameters of the spheres are 3 cm, so the radii are 1.5 cm.
OpenStudy (anonymous):
*radius is 1.5
OpenStudy (isuckatschool43):
14.14
OpenStudy (anonymous):
dang thats why im in middle school
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OpenStudy (anonymous):
V = (4/3)pi r^3
V = (4/3) * 3.14 * (1.5)^3 14.13 cm^3
25 spheres have a volume of 25 * 14.13 = 353.25 cm^3
Now subtract 602.88 cm^3 - 353.25 cm^3
OpenStudy (isuckatschool43):
249.63 cm^3
OpenStudy (anonymous):
actually hold up
OpenStudy (anonymous):
multiply 14.14 by 25
OpenStudy (isuckatschool43):
353.5
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OpenStudy (isuckatschool43):
oh
OpenStudy (anonymous):
353.5 right
OpenStudy (anonymous):
\[603.19-353.5=?\]
OpenStudy (isuckatschool43):
249.38
OpenStudy (anonymous):
close but not quite
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OpenStudy (isuckatschool43):
.69
OpenStudy (anonymous):
perfect
OpenStudy (anonymous):
I'm fairly sure that that is the correct answer but I'm not a math wiz lol.
OpenStudy (isuckatschool43):
okay. i have 2 left
OpenStudy (anonymous):
Okay....... This time please start a new question and tag me... :)
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OpenStudy (isuckatschool43):
ok
OpenStudy (anonymous):
So the first is definitely correct @isuckatschool43
OpenStudy (anonymous):
I'm gonna recalculate the second one now
OpenStudy (isuckatschool43):
ok
OpenStudy (anonymous):
\[v=3.14(4^{2})(12)\]
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OpenStudy (anonymous):
which would equal 602.8
OpenStudy (isuckatschool43):
i got 602.88
OpenStudy (anonymous):
correct
OpenStudy (isuckatschool43):
so your 353.25 was correct
OpenStudy (isuckatschool43):
so it is 602.88 - 353.25 = 249.63
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OpenStudy (anonymous):
\[v =\frac{ 4 }{ 3 }(3.14)(1.5^{3})\]
OpenStudy (anonymous):
Yes that's correct :)
OpenStudy (isuckatschool43):
okay so we got that patched up
OpenStudy (anonymous):
Yah so sorry about that :(
OpenStudy (isuckatschool43):
yeah it isnt your fault i didnt point it out
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OpenStudy (anonymous):
No but I should've paid better attention lol. You have anymore that you need help on?
OpenStudy (isuckatschool43):
yeah just 1 more but it is pretty easy. i dont think i need help on it
OpenStudy (anonymous):
Okay well tag me or pm me if you ever want help again
OpenStudy (isuckatschool43):
thank you so much for all the help, everything was right :D
OpenStudy (anonymous):
You're welcome. Thanks for bearing with me. Have a good rest of the day
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