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Mathematics 15 Online
OpenStudy (isuckatschool43):

Please help me I will fan and medal

OpenStudy (scarlettfarra2000):

What's the problem?

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

sorry i got distracted @ScarlettFarra2000

OpenStudy (anonymous):

ok.....

OpenStudy (isuckatschool43):

i did the formula and got that number

OpenStudy (isuckatschool43):

am i right?

OpenStudy (scarlettfarra2000):

http://www.tiger-algebra.com/drill/3/4(3.14)(18~2)/ try that website and see if it helps

OpenStudy (anonymous):

So it's asking how much larger the other ball is.... From what I can tell you only calculated one ball.... Maybe I'm misunderstanding the question but I would think that you would calculate the other ball next with the same equation.....

OpenStudy (anonymous):

\[v=\frac{ 4 }{ 3 }(3.14)(12^{3 })\]

OpenStudy (anonymous):

solve that please

OpenStudy (isuckatschool43):

7234.56

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

so try this next....

OpenStudy (anonymous):

\[24,416.64-7,234.56\]

OpenStudy (isuckatschool43):

17,182.08

OpenStudy (anonymous):

I'm pretty sure that is the answer.

OpenStudy (isuckatschool43):

ok. i have a few more if you have time

OpenStudy (anonymous):

yes i think you got it right

OpenStudy (anonymous):

Ok just tag me whenever you need me

OpenStudy (anonymous):

i did do you know history?

OpenStudy (isuckatschool43):

should i open a new question or just post it here

OpenStudy (anonymous):

new question

OpenStudy (anonymous):

it doesn't matter. it's up to you

OpenStudy (isuckatschool43):

ok

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

im also thinking 150.72...

OpenStudy (anonymous):

give me a sec

OpenStudy (isuckatschool43):

ok

OpenStudy (anonymous):

Ok so I think that you would start by using the following formula

OpenStudy (anonymous):

\[v =3.14(4^{2})12\]

OpenStudy (anonymous):

basically it's v=3.14(r^2)h

OpenStudy (anonymous):

dang what grade are youll in thats too confussing?

OpenStudy (anonymous):

I'm a junior... @s10539609 Sorry let me know if I confuse you @isuckatschool43

OpenStudy (anonymous):

type in calculate a cylinder on google then put 4 for the radius and 12 for the height

OpenStudy (isuckatschool43):

603.19

OpenStudy (anonymous):

@imqwerty @zepdrix

OpenStudy (anonymous):

Okay good now you need to find the volume of the spheres of ice: The diameters of the spheres are 3 cm, so the radii are 1.5 cm.

OpenStudy (anonymous):

*radius is 1.5

OpenStudy (isuckatschool43):

14.14

OpenStudy (anonymous):

dang thats why im in middle school

OpenStudy (anonymous):

V = (4/3)pi r^3 V = (4/3) * 3.14 * (1.5)^3 14.13 cm^3 25 spheres have a volume of 25 * 14.13 = 353.25 cm^3 Now subtract 602.88 cm^3 - 353.25 cm^3

OpenStudy (isuckatschool43):

249.63 cm^3

OpenStudy (anonymous):

actually hold up

OpenStudy (anonymous):

multiply 14.14 by 25

OpenStudy (isuckatschool43):

353.5

OpenStudy (isuckatschool43):

oh

OpenStudy (anonymous):

353.5 right

OpenStudy (anonymous):

\[603.19-353.5=?\]

OpenStudy (isuckatschool43):

249.38

OpenStudy (anonymous):

close but not quite

OpenStudy (isuckatschool43):

.69

OpenStudy (anonymous):

perfect

OpenStudy (anonymous):

I'm fairly sure that that is the correct answer but I'm not a math wiz lol.

OpenStudy (isuckatschool43):

okay. i have 2 left

OpenStudy (anonymous):

Okay....... This time please start a new question and tag me... :)

OpenStudy (isuckatschool43):

ok

OpenStudy (anonymous):

So the first is definitely correct @isuckatschool43

OpenStudy (anonymous):

I'm gonna recalculate the second one now

OpenStudy (isuckatschool43):

ok

OpenStudy (anonymous):

\[v=3.14(4^{2})(12)\]

OpenStudy (anonymous):

which would equal 602.8

OpenStudy (isuckatschool43):

i got 602.88

OpenStudy (anonymous):

correct

OpenStudy (isuckatschool43):

so your 353.25 was correct

OpenStudy (isuckatschool43):

so it is 602.88 - 353.25 = 249.63

OpenStudy (anonymous):

\[v =\frac{ 4 }{ 3 }(3.14)(1.5^{3})\]

OpenStudy (anonymous):

Yes that's correct :)

OpenStudy (isuckatschool43):

okay so we got that patched up

OpenStudy (anonymous):

Yah so sorry about that :(

OpenStudy (isuckatschool43):

yeah it isnt your fault i didnt point it out

OpenStudy (anonymous):

No but I should've paid better attention lol. You have anymore that you need help on?

OpenStudy (isuckatschool43):

yeah just 1 more but it is pretty easy. i dont think i need help on it

OpenStudy (anonymous):

Okay well tag me or pm me if you ever want help again

OpenStudy (isuckatschool43):

thank you so much for all the help, everything was right :D

OpenStudy (anonymous):

You're welcome. Thanks for bearing with me. Have a good rest of the day

OpenStudy (isuckatschool43):

You too!

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