Mathematics
8 Online
OpenStudy (rootbeer003):
What value should be added to the expression to create a perfect square?
x^2 + 16x
8
16
64
4
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OpenStudy (rootbeer003):
was thinkin 16
OpenStudy (rootbeer003):
wait no 4
OpenStudy (anonymous):
two steps only
and no, not 16
no not that either
OpenStudy (anonymous):
what is half of 16? that is step one
TheSmartOne (thesmartone):
Half of 16
And square it
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OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
8
OpenStudy (anonymous):
second step
what is \(8^2\)?
OpenStudy (rootbeer003):
64
OpenStudy (anonymous):
done
finished
next ...
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TheSmartOne (thesmartone):
Bingo
OpenStudy (rootbeer003):
hold up
OpenStudy (anonymous):
holding...
OpenStudy (rootbeer003):
OpenStudy (anonymous):
\[2x^2-2x-1=0\] solve via \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=2,b=-2,c=-1\] or cheat
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OpenStudy (rootbeer003):
so i right?
OpenStudy (anonymous):
yes
OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
c?
OpenStudy (anonymous):
\[b^2-4ac\] with \(a=1,b=-3,c=5\) i.e. \[(-3)^2-4\times 1\times 5\]
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OpenStudy (anonymous):
oh yea, C
OpenStudy (rootbeer003):
OpenStudy (anonymous):
what is \(b^2-4ac\) here?
OpenStudy (rootbeer003):
wat
OpenStudy (anonymous):
let me know when you get \(36-12=24\)
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OpenStudy (anonymous):
important part is that it is a positive number
that means there are two real solutions
OpenStudy (rootbeer003):
OpenStudy (anonymous):
why the stupid restrictions? just graph it here
OpenStudy (anonymous):
only question is, can you read the graph to answer the question
is the vertex above or below the x axis?
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OpenStudy (anonymous):
i need a drink, brb
OpenStudy (rootbeer003):
above?
OpenStudy (anonymous):
does it look like it is above to you !!??|dw:1455849839372:dw|
OpenStudy (anonymous):
|dw:1455849905654:dw|