Question

Hm._. a post

Answer 1

I don't know dis :3

Answer 2

@mathmale here i did like this :3 the second post

Answer 3

I see you have one multiplicand, -a^2*b^2*c^2, that is outside the parentheses.
Inside the parentheses you have 3 terms.

You are to multiply each of those 3 terms, one by one by -a^2*b^2*c^2.
Hint: -a^2 * a = - a^3

Answer 4

Questions about this procedure? In what area do you need guidance?

Answer 5

wait so i multiply all of them?? :3

Answer 6

@Astrophysics umm i have no idea ;~;

Answer 7

Hey

Answer 8

Hi :3

Answer 9

So note the exponent rule \[\huge x^n x^m = x^{n+m}\]

This is saying when you have a same variable, but different exponents (integers) when you multiply you add the exponents.

So I'll do the first one for you, we are just distributing here: \[\large (-a^2b^2c^2)(a+b-c) \implies -a^{2+1}b^2c^2+(-a^2b^{?+?}c^2)-...\]

Answer 10

See if that makes sense

Answer 11

Oh okay I'm looking thrue it

Answer 12

do i have to continue with a?

Answer 13

so the last one is a - * - which is a positive you have the last term left to do, also I left the second term as b^2b so you can practice the exponent rule, see if you can finish it off