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Algebra
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Expand the Logarithm Log6 2x/y
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The 6 is the base?
yes :)
We used our division rule in the last problem, now we want to use it in the reverse direction,\[\large\rm \log\left(\frac{a}{b}\right)=\log(a)-\log(b)\]
Do you see how that will help us break the 2x away from the y?
the 2x stays together?
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yes, for now.
so Log (2x) - Log (y)??
log(2x/y) = log(2x) - log(y) mmm k great, first step is done.
or Log6 (2x) - Log6 (y)
yes, we probably shouldn't ignore the base of the log :) my bad
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yeah haha :)
then what?
Then apply your multiplication rule to the 2 and x, log(ab) = log(a) + log(b)
so log6 (2) + Log6 (x) ?
?
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oh sorry got busy XD yes.
log6(2x/y) = log6(2)+log6(x)-log6(y) yay team \c:/
its okay :)
is that it?
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