Question

Help on two calculus questions..

Answer 1

Im stuck at:

(8(6x^2 -7x +4)^7 )( 12x -7)

Answer 2

Product Rule (ab)'=ab'+a'b

Answer 3

you need to use the product rule

Answer 4

What does that look like again?

Answer 5

ignore the 8 (for the moment)
then it is the first term (big mess) times the derivative of the 2nd term
then add that to 2nd term times the derivative of the first term

finally, multiply that sum by the 8

Answer 6

Okay one second

Answer 7

So..
(6x^2 -7x +4)^7 (12x-7) +(12x-7) (6x^2 -7x +4)^7

or is ^^^ and ^^^ supposed to be smaller?

Answer 8

you want derivative of 12x-7 in the first part
and the derivative of the ( )^7 stuff in the second part

Answer 9

you want
\[ (6x^2 -7x +4)^7 \frac{d}{dx} (12x-7) +(12x-7)\frac{d}{dx} (6x^2 -7x +4)^7 \]

Answer 10

Oh okay

Answer 11

and of course all of that times 8

Answer 12

So next I solve the d/ dx parts first. The multiply everything one by one right?

Answer 13

Then *

Answer 14

I would write down the derivatives (and remember the chain rule)
and see what is what before forging ahead.

Answer 15

d/ dx (6x^2 -7x +4) = 12x-7 or just 12x?

Answer 16

you take the derivative of a sum term by term. so the first is the answer
(d/dx of 4 is 0)

Answer 17

Yes.

Answer 18

Sorry I have to leave for 40 minutes. Will you still be able to help me once im back?

Answer 19

maybe.

Answer 20

Because of the length of this conversation, I'd suggest you post your 2nd question separately.

Answer 21

This question isn't that long.

Answer 22

Hi, still need help?

Answer 23

Yes I do

Answer 24

Where are you stuck?

Answer 25

Here:

8((6x^2 -7x +4) ^7 d/dx (12x-7) + (12x-7) d/dx (6x^2 -7x +4)^7)

Answer 26

Right, so you applied the power rule and you noticed we need chain rule.

Answer 27

this is your first derivative correct