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Mathematics 21 Online
OpenStudy (study312):

Please help, I need some help quickly. its kinda about area.

OpenStudy (study312):

A candy bar box is in the shape of a triangular prism. The volume of the box is 2,400 cubic centimeters. A triangular prism is shown with base of triangle labeled 16 cm, sides of triangles labeled 17 cm, and length of the box equal to 20 cm. Part A: What is the height of the box? Show your work. (5 points) Part B: What is the approximate amount of cardboard used to make the sides of the candy box? Explain how you got your answer. (5 points)

OpenStudy (study312):

OpenStudy (study312):

Can you guys please help?

OpenStudy (jdoe0001):

covered the pythagorean theorem yet?

OpenStudy (study312):

it doesn't ring a bell

OpenStudy (study312):

would the height be 17?

OpenStudy (jdoe0001):

ahemm nope, that's just the "slanted height", not altitude but you'd want to cover the pythagorean theorem first though check your book on it

OpenStudy (jdoe0001):

since you'd need it to get the altitude

OpenStudy (study312):

this is online so I don't have a book

OpenStudy (jdoe0001):

so, that means you're exempted from stydying?

OpenStudy (study312):

and the lessons didn't cover it

OpenStudy (study312):

what

OpenStudy (study312):

I don't remember them talking about these problems

OpenStudy (jdoe0001):

well... then... kinda makes this exericse not applicable then since you haven't covered it

OpenStudy (study312):

well can you help or not?

OpenStudy (jdoe0001):

do I know the pythagorean theorem? yes does that help you? nope the issue is, the exericse is meant to use it and thus you'd have to cover that first, how it works, what are the ratios, what are the relations, when it works, when it doesn't so... you'd need to cover it first I'd think

OpenStudy (jdoe0001):

so, if you haven't covered it, the exercise doesn't apply to you can someone here do it for you? sure will that "help" you? depends on what you mean by "help" if you mean understand it, nope they'll do it, but you wouldn't know what or why they did

OpenStudy (study312):

Well I got the jist

OpenStudy (kayders1997):

Well if you tell him/her what the pythagorean theorem than maybe they will remember it I don't understand why you cant say that it is just a formula this person will probably have to use more in geometry

OpenStudy (study312):

sigh

OpenStudy (study312):

oh well it can be blank

OpenStudy (kayders1997):

X^2 + y^2 = z^2

OpenStudy (study312):

huh

OpenStudy (kayders1997):

Thats the theorem

OpenStudy (kayders1997):

Than you have to split the triangle base in half to find the height

OpenStudy (kayders1997):

So what is your base?

OpenStudy (study312):

16

OpenStudy (kayders1997):

Yes so you have to cut that in half because when you are finding another side of a triangle you need to have a right angle so half of that is?

OpenStudy (study312):

8

OpenStudy (kayders1997):

Yep so that will be the base now and what is the other side they give you?

OpenStudy (study312):

20?

OpenStudy (kayders1997):

Not quite, for the triangle part

OpenStudy (kayders1997):

Whats the other side of the triangle?

OpenStudy (study312):

oh 17

OpenStudy (kayders1997):

Yes so you have sides 8 and 17 the17 doesn't get cut in half, because its the hypotenuse line, so you can almost call this b^2+h^2=l^2 where b is base h is height, and l will be the hypotenuse, does this make sence?

OpenStudy (kayders1997):

Or long side for l because hypotenuse is always the longest side in a triangle

OpenStudy (kayders1997):

@study312

OpenStudy (study312):

sorry afk

OpenStudy (kayders1997):

Afk?

OpenStudy (study312):

Away, From, Keyboard

OpenStudy (kayders1997):

And does this stuff make sense?

OpenStudy (study312):

more or less

OpenStudy (kayders1997):

Okay

OpenStudy (kayders1997):

If you have a question let me know

OpenStudy (study312):

what now?

OpenStudy (study312):

is the height 8?

OpenStudy (kayders1997):

So b=8 and l=17 So we use this formula b^2 + h^2 = l^2 So we plug in 8 for b and 17 for l 8^2+h^2=17^2

OpenStudy (kayders1997):

So whats 8^2 and 17^2?

OpenStudy (study312):

8 x 8 is 64 and 17 x 17 is 289

OpenStudy (kayders1997):

Yes so now you have 64+h^2=289 how do you isolate to have just h^2 left?

OpenStudy (study312):

find the square of 289?

OpenStudy (study312):

are we still figuring out the height?

OpenStudy (kayders1997):

Nope because you still have the 64 you want to get the 64 to the other side and have h^2 on one sode

OpenStudy (kayders1997):

Yes were almost done

OpenStudy (study312):

289 ÷ 2

OpenStudy (kayders1997):

64+h^2=289 you have to subtract by 64 from both sides so h^2 is alone on one side and 289 minus 64 is? Does this make sense?

OpenStudy (study312):

yes. 225

OpenStudy (kayders1997):

So h^2=225 do you know how to get it to just be h=

OpenStudy (study312):

225 ÷ 2

OpenStudy (kayders1997):

Nope that would be 2h

OpenStudy (kayders1997):

If you have the square root what would you do?

OpenStudy (study312):

well I use a calculator

OpenStudy (study312):

and its 15

OpenStudy (kayders1997):

Yes it is

OpenStudy (kayders1997):

I don't know how to do the second part :(

OpenStudy (study312):

ok thx

OpenStudy (study312):

I think it is just area

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