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Mathematics 21 Online
OpenStudy (rootbeer003):

check my answer?

OpenStudy (rootbeer003):

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

as in "yes your answer is right"

OpenStudy (anonymous):

happy now?

OpenStudy (rootbeer003):

ya

OpenStudy (rootbeer003):

OpenStudy (rootbeer003):

how bout dis

OpenStudy (anonymous):

\[\frac{(x+6)(x-6)}{x-6}=x+6,x\neq 6\]

OpenStudy (anonymous):

i.e. yes you are correct as usual

OpenStudy (rootbeer003):

U READY TO DO SOME HARD CORE HELPING

OpenStudy (anonymous):

no i am read for beer

OpenStudy (anonymous):

lets get it done in thirty minutes tops

OpenStudy (rootbeer003):

wow ur a great influence

OpenStudy (anonymous):

oh right sorry i meant "root beer"

OpenStudy (rootbeer003):

OpenStudy (anonymous):

cancel \(y^2\) and an \(x\) left with \(80x^2\)

OpenStudy (rootbeer003):

uhuh

OpenStudy (anonymous):

ok back

OpenStudy (rootbeer003):

k

OpenStudy (rootbeer003):

is it a?

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (anonymous):

any guesses? just cancel some stuff

OpenStudy (rootbeer003):

b?

OpenStudy (anonymous):

no, because \(\frac{20}{10}=2\) should have a 2 up top

OpenStudy (anonymous):

also x up top, y in the bottom

OpenStudy (rootbeer003):

c

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (anonymous):

i hate this crap factor and cancel

OpenStudy (rootbeer003):

well theres a reason im asking u

OpenStudy (anonymous):

looks like \[\frac{3(x+2)}{x+1}\]

OpenStudy (rootbeer003):

so im right?

OpenStudy (anonymous):

yes as usual

OpenStudy (rootbeer003):

OpenStudy (anonymous):

yes again

OpenStudy (rootbeer003):

OpenStudy (anonymous):

yes again

OpenStudy (rootbeer003):

how much more time u got?

OpenStudy (anonymous):

idk i will tell you when i drop

OpenStudy (anonymous):

how many more you got?

OpenStudy (rootbeer003):

atun

OpenStudy (anonymous):

lets do five

OpenStudy (rootbeer003):

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (anonymous):

no, you need the 50 also \(x^4\) and \(y^3\)

OpenStudy (rootbeer003):

d

OpenStudy (anonymous):

not common factors, least common multiple yeah D

OpenStudy (rootbeer003):

OpenStudy (anonymous):

nope same mistake as before you need both \(x^2\) and \(y^2\)

OpenStudy (rootbeer003):

wait no d

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (anonymous):

heck no that is not how you add fractions

OpenStudy (rootbeer003):

a

OpenStudy (anonymous):

\[\frac{2}{9x^3}+\frac{5}{3x}\] lcd is \(9x^3\) so \[\frac{2}{9x^3}+\frac{5}{3x}\times \frac{3x^2}{3x^2}\] \[=\frac{2}{9x^3}+\frac{15x^2}{9x^3}=\frac{2+15x^2}{9x^3}\]

OpenStudy (anonymous):

you do not add the tops until you have the correct denominator

OpenStudy (rootbeer003):

b

OpenStudy (anonymous):

yes

OpenStudy (rootbeer003):

OpenStudy (anonymous):

stop it !~

OpenStudy (anonymous):

you do not subtract like that

OpenStudy (anonymous):

\[\frac{a}{b}-\frac{c}{d}=\frac{ad-bc}{bd}\]

OpenStudy (anonymous):

\[\frac{10}{w}-\frac{1}{3}\] \[=\frac{3\times 10-w\times 1}{3\times w}\]

OpenStudy (rootbeer003):

c

OpenStudy (anonymous):

oh right C

OpenStudy (rootbeer003):

ok lag bye

OpenStudy (anonymous):

bye !

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