If a 2.5 g sample of gold is hammered into an equilateral triangle that is .28mm thick, how long are the sides?
Okay, let's first determine the volume of the triangle. Volume of the triangle = Mass of the triangle/Density of gold = 2.5/19.3 = 0.129533678cm³ 1mm= 0.1cm 0.28mm= (0.1)(0.28) = 0.028cm Volume of a solid = (area of its cross section)(thickness) Area of the triangle = Volume/thickness = 0.129533678/0.028 = 4.626202813cm²
I think I know how to do it. I need to find the height or something right? :/
Oh ok
that works too
wait where did you get the 19.3 from?
Multiplying them
Now, in an equilateral triangle, each angle is 60°. The area of a triangle is determined using the formula (1/2)absin60°, where a and b are the lengths of two of its sides. Since a=b in the case of the equilateral triangle, its area= (1/2)L²sin60°, where L is the length of each of its sides. (1/2)L²sin60°= 4.626202813 L²= (2)(4.626202813)/sin60° L²= 10.68375776 L= |√10.68375776| = 3.268601805cm = 3.3cm correct to 2 significant figures
Does that answer your question? :)
Somewhat....
How could I figure out the lenght of the sides though?
Now I'm just confused.. :/
The answer is = 3.268601805cm
Really? For all three sides?
For 2
actually
Oh yeah beacuse it is an equilateral triangle which means all sides are the same
L²= (2)(4.626202813)/sin60° L²= 10.68375776 L= |√10.68375776|
Those are the sides
So does it make sense now?
and yes it is because its equilateral triangle :)
Yeah! So the two answers are the 10.6 and 3.26?
All three sides are 10.6 :D GoodJob
Thank you!
You're welcome :)
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