Question

Summation of 200C2+ 200C10+ 200C18+ 200C26+200C34+....upto 200C194 ????

Answer 1

@phi

Answer 2

@michele_laino

Answer 3

?

Answer 4

Didn't u get my question?

Answer 5

Nah

Answer 6

Well that C is from binomial theorem

Answer 7

@parthkohli

Answer 8

@phi

Answer 9

Interesting. The general way to solve these problems is to use complex numbers.

Answer 10

It"z like the series is 200C8r-6

Answer 11

With summation up to r=25

Answer 12

Correct.
Whenever you're given \(r\) in the \(\binom{n}r\) as an arithmetic progression, use complex numbers. Let me explain how.

Answer 13

Okay!

Answer 14

Well do u want to say that we will find roots of (1)^1/8 n put them into it...
The binomial

Answer 15

Yes, but that's the general way and life is too short for that.

Answer 16

Ohh!!! Then what is the better way out ?

Answer 17

Nothing, just have to repeat a process again and again.