Question

Please help on graphing this function y= 3sin (2theta +pi/3) +5
More details below

Answer 1

How to graph these functions:
a. y=\[3\sin (2\theta + \frac{ \pi }{ 3 })+5\]
b. \[y = 3\sin (\frac{ \theta }{ 2}-\frac{ \pi }{ 6 }) - 4\]

In this graph:

Answer 2

a.) Amplitude = 3
Period = π
Phase Displacement = π/6
Vertical Translation = 5

b.) Amplitude = 3
Period = 4π
Phase Displacement = -π/3
Vertical Translation = 4

Are these values correct and how do I graph them?

Answer 3

I've noticed that your original function doesn't have an independent variable. Insert one, please.

Answer 4

@mathmale what do you mean? That's exactly how it is in the given/

Answer 5

I don't know this exactly but this hopefully helps you a bit https://answers.yahoo.com/question/index?qid=20110508155922AAi6zs8

Answer 6

Hey Bird :)
You still around?

Answer 7

a.) Amplitude = 3
Period = π
Phase Displacement = π/6
Vertical Translation = 5

Information looks good!
I would say that the phase displacement is -π/6 though,
since it's going to be a horizontal shift to the left.

Answer 8

@zepdrix Hi, so how do I graph this? I'm just concerned on where the points will be in the x-axis.

Answer 9

ok great you labeled your y-axis according to your amplitude.
Let's leave the x-axis unlabeled for now,
it will make things easier in the end.