Question

A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below:

The figure shows a silo shaped as a closed cylinder with a conical end. The diameter of the silo is 4 ft, the length of the cylindrical part is 8.5 ft, and the entire length of the silo is 13 ft.

Which of the following could be used to calculate the total volume of grains that can be stored in the silo?

Answer 1

options:

a:pi(8.5ft)^2(2ft) + 1/3pi(2ft)^2(13ft-8.5ft)
b:pi(2ft)^2(8.5ft) + 1/3pi(2ft)^2(13ft-8.5ft)
c:pi(8.5ft)^2(2ft) + 1/3pi(13ft - 8.5ft)^2(2ft)
d:pi(2ft)^2(8.5ft) + 1/3pi (13ft- 8.5ft) ^2(2ft)

Answer 2

@Ineedhelplz and @Michele_Laino help again?

Answer 3

Do you know what the area of the cylinder part is?

Answer 4

Hint, \[\text{Area of circle} = \pi r^2\]

Answer 5

a= 2pi r h + 2pir^2

Answer 6

What formula is that?

Answer 7

area of a cylinder...

Answer 8

\[\text{Volume of Cylinder} = h_c\pi r^2 \] where h_c is the height of the cylinder.

Answer 9

Oh, the question is asking for Volume I think.

Answer 10

oh ok

Answer 11

the requested volume is given by the sum of the volume of the cylinder whose height is 8.5 feet with the cone whose height is \(13-8.5=4.5\) feet. So we can write:
\[V = \left( {\pi \times {2^2} \times 8.5} \right) + \left( {\frac{{\pi \times {2^2} \times 4.5}}{3}} \right) = ...?\]