question
\(\dfrac{p}{q}=\dfrac{6}{5}\) \(q\) is what \(\%\) more/less than \(p\ \) ?
do you know about "dividendo" ?
\(\large \color{black}{\begin{align} & \dfrac{p-q}{q}=\dfrac{1}{5}\hspace{.33em}\\~\\ \end{align}}\)
oh so you know.... i was gonna ask you to apply invertendo first, and then dividendo :P
\(\large \color{black}{\begin{align} & \dfrac{q-p}{p}=\dfrac{-1}{6}\hspace{.33em}\\~\\ \end{align}}\)
because we want, how much % is q less/more than p, so we need \(\large \dfrac{p-q}{p}\)
yeah, good
to get the % just multiply that result by 100 :)
\(\large \color{black}{\begin{align} & \dfrac{p-q}{p}=16.66\cdots \%\hspace{.33em}\\~\\ \end{align}}\)
yep so, q is 16.67% less than p :)
\(\large \color{black}{\begin{align} thanks \hspace{.33em}\\~\\ \end{align}}\)
\(\text{welcome ^_^}\)
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