Use Einstein’s energy equation to solve the following problem. Recall that the speed of light is 3 × 108 m/s.
If a 5.0-kg stone is completely converted to energy, what is its energy equivalent in joules?
4.5 × 10^17 J
1.5 × 10^10 J
1.5 × 10^9 J
4.5 × 10^15 J
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OpenStudy (andrewkaiser333):
@jim_thompson5910
OpenStudy (andrewkaiser333):
@anyone
OpenStudy (anonymous):
\(\sf E= mc^2\) , where m is the mass (5 kg) & c is the speed of light ( 3 × 108 m/s) .
All you have to do is substitute the given values.
OpenStudy (andrewkaiser333):
i am not to good with that equation
jimthompson5910 (jim_thompson5910):
Given info
\[\Large m = 5\]
\[\Large c = 3 \times 10^8\]
plug them into the formula
\[\Large E = mc^2\]
\[\Large E = 5*\left(3 \times 10^8\right)^2\]
then evaluate
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OpenStudy (andrewkaiser333):
oh ok
OpenStudy (andrewkaiser333):
(15*50^8)^2
jimthompson5910 (jim_thompson5910):
btw,
\[\Large 3 \times 10^8 = 300,000,000\]
which is the number `300 million`
jimthompson5910 (jim_thompson5910):
PEMDAS says you have to do exponents before multiplication
jimthompson5910 (jim_thompson5910):
you cannot multiply the 5 and 3 because the 3 is under an exponent
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OpenStudy (andrewkaiser333):
ok then can u show me? i am confused
OpenStudy (andrewkaiser333):
Like i said not too good with this formula
jimthompson5910 (jim_thompson5910):
\[\Large E = 5*\left(3 \times 10^8\right)^2\]
\[\Large E = 5*\left(3\right)^2*\left(10^8\right)^2\]
\[\Large E = 45*\left(10^8\right)^2\]
I'll let you finish up
OpenStudy (andrewkaiser333):
45*10^10 ?
jimthompson5910 (jim_thompson5910):
you won't add the exponents in this case
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OpenStudy (andrewkaiser333):
how?
jimthompson5910 (jim_thompson5910):
when you raise an exponential expression to another exponent, you multiply the exponents
jimthompson5910 (jim_thompson5910):
example:
\[\Large (2^3)^5 = 2^{3*5} = 2^{15}\]
OpenStudy (andrewkaiser333):
ok so 8*2= 45*10^16
jimthompson5910 (jim_thompson5910):
now convert \[\Large 45 \times 10^{16}\] to scientific notation
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OpenStudy (andrewkaiser333):
4.5*10^16 ???
jimthompson5910 (jim_thompson5910):
no
OpenStudy (andrewkaiser333):
then what??
jimthompson5910 (jim_thompson5910):
it might help to think of 45 as 4.5*10^1
OpenStudy (andrewkaiser333):
ok?
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