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Mathematics 17 Online
OpenStudy (superfly123):

Helpp

OpenStudy (ineedhelplz):

I made it in a word doc if I send a picture, will you be able to view it?

imqwerty (imqwerty):

yes you can attach the document using the "Attach file" tool :) http://prntscr.com/a5ybup

OpenStudy (ineedhelplz):

Thank you @imqwerty :)

imqwerty (imqwerty):

np :) that image is solution to other similar question tho it is helpful well if you prove that ABCD is a parallelogram which is a rhombus then you just need to prove that all its sides are congruent

Directrix (directrix):

I think that the given diagram is not marked up correctly. It should be AE = EC marked rather than those angles.

OpenStudy (anonymous):

@Directrix can u help me

OpenStudy (superfly123):

oh

imqwerty (imqwerty):

i mean *quadrilateral not parallelogram

imqwerty (imqwerty):

no its alright we can do it in 11 steps :)) well we can't say that the quadrilateral is a rhombus just by stating that the diagonals are perpendicular, there are more things to concern consider this case-|dw:1456018555576:dw| here ABCD has perpendicular diagonals but the sides are not congruent so its not a rhombus

imqwerty (imqwerty):

alright so lets start with the proof all information given to us-> \(\angle CED=right ~angle\) \(AB \equiv CD\) DB bisects AC at E \(\angle DCA \equiv \angle BAC\) \(\angle DEA\) =right angle right?

imqwerty (imqwerty):

we look at \(\Delta ABC \) and \(\Delta ADC\) here \(AC=AC\) (common side) \(\angle DCA \equiv \angle BAC\) (given) \(AB=DC\) (given) so therefore \(\Delta ABD \equiv \Delta ADC\) by ASA theorem so we can say that \(AD=BC\) by CPCT \({\angle AEB= \angle DEC = 90 ~~~(vertically~opposite~angles)\\ ~ \angle BEC= \angle ADE =90}~~~(vertically~opposite~angles)\) now look at \(\Delta BEC \) and \(\Delta ABE\) here \(EC=AE\) (because DB bisects AC at E) \(BE=BE\) (common side) \(\angle AEB = \angle BEC\) (both equal to 90 degrees ) so \(\Delta BEC \equiv \Delta ABE\) by ASA theorem so \(AB=AC\) by CPCT so \(AB=BC=CD=DA\) all sides are congruent so ABCD is a rhombus

jhonyy9 (jhonyy9):

@SuperFly123 than you check your posted question in the past day to this your question i have wrote a proofe yestoday or before - try get it there please

imqwerty (imqwerty):

we don't need to talk about diagonals if all the sides are congruent :)

jhonyy9 (jhonyy9):

some days ago i have replid an posted question like this to prove that a quadrilateral is rhombus - sorry than not you was who posted it

jhonyy9 (jhonyy9):

not exactly just on the question and the question was exactly like your posted here above

jhonyy9 (jhonyy9):

i will try than i wil can get it now - ok.?

OpenStudy (ineedhelplz):

Ok

OpenStudy (ineedhelplz):

OpenStudy (superfly123):

How do i show all four are right angles?

OpenStudy (ineedhelplz):

Wait, they don't have to be in order

OpenStudy (ineedhelplz):

look at the document I tried to do it for you I'm not sure if its what you need...

OpenStudy (ineedhelplz):

You show that that they are right angles witht t|dw:1456077407914:dw|

OpenStudy (ineedhelplz):

That little symbol

OpenStudy (superfly123):

Kind of helpful the document , idk

OpenStudy (ineedhelplz):

So is it what you need?

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