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Mathematics 17 Online
OpenStudy (anonymous):

Can someone please help me with two simple Cal Equations

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 @hartnn @Zarkon

OpenStudy (priyar):

what eq can u write?

OpenStudy (anonymous):

i cant think of one

OpenStudy (priyar):

dP/dt (where P-population)=?

OpenStudy (priyar):

u have learnt these right?

OpenStudy (anonymous):

yes

OpenStudy (priyar):

ok then what is the rate of change of population?

OpenStudy (priyar):

dP/dt =?

OpenStudy (anonymous):

actually i dont get it

OpenStudy (anonymous):

can i just get the answer please

OpenStudy (priyar):

well..u must learn the concept behind it.. is suggest u look at some sample problems in ur book..i would have given an example but i m in a hurry..sry.. and Good Luck!

OpenStudy (snowsurf):

What you do not get?

OpenStudy (anonymous):

the answer

OpenStudy (snowsurf):

Are you given the equation?

OpenStudy (anonymous):

no

OpenStudy (snowsurf):

Okay. Let's derive it.

OpenStudy (episode):

Hello, we can model this equation, we can this will require a differential equation of the sort \[\frac{ dy }{ dt } = ky\] which give us the exponential functions \[y(t)=y(0)e^{kt}\] so in our case as we're dealing with population growth we can use the following: \[\frac{ dP }{ dt } = kP\] where k is the proportionality constant. And our relative growth will be \[\frac{ 1 }{ P }\frac{ dP }{ dt }\] which should be constant. So our equation then becomes \[P(t)=P_0e^{kt}\]

OpenStudy (episode):

Our initial population is \(P_0\) t = time k = relative growth P(t) = population at a time t

OpenStudy (episode):

You may use this equation now to answer your questions

OpenStudy (anonymous):

wait can you show me this in context

OpenStudy (anonymous):

could you show me he equation plugged into the question

OpenStudy (episode):

Ok, lets put all the information we have down first, can you do that please?

OpenStudy (anonymous):

sure

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