Question

Can someone help me with this cal problem

Answer 1

Hey I just showed you this

Answer 2

yeah but you quit on me

Answer 3

can someonel please help me

Answer 4

You did not answer what I had asked you off: So again

we can model this equation, this will require a differential equation of the sort \[\frac{ dy }{ dt } = ky\] which give us the exponential functions \[y(t)=y(0)e^{kt}\] so in our case as we're dealing with population growth we can use the following: \[\frac{ dP }{ dt } = kP\] where k is the proportionality constant. And our relative growth will be \[\frac{ 1 }{ P }\frac{ dP }{ dt }\] which should be constant. So our equation then becomes \[P(t)=P_0e^{kt}\]

Now as I asked you last time, please write down all the information they have gave us.

Answer 5

Our initial population is \(P_0\)
t = time
k = relative growth rate
P(t) = population at a time t

Answer 6

P(t)=18000e^10(2)

Answer 7

is that it?

Answer 8

?????

Answer 9

Not quite, you listed the initial population as 18,000 but that's not right.

P(t) should be 18000, we need to solve for \(P_0\)

Answer 10

ok

Answer 11

so its 18000=Psub0e^20

Answer 12

What does the population doubles every 10 years mean?

Answer 13

i dont know how to write it out

Answer 14

this problem is due for me in 10 minutes could you please help me quickly

Answer 15

Ok solve for \[P_0 \] here \[18000 = P_0 2^{25/10}\]

Answer 16

and for part b) you should get \[18000 \times 2^{7/10}\]

Answer 17

ok can you help me out with this one too starting from part b

Answer 18

Well what kind of function would you expect looking at the graph?

Answer 19

slope

Answer 20

idk

Answer 21

can you walk me through it