Find an equation for the nth term of the arithmetic sequence. 8, 6, 4, 2, ...
so what is happening here?
what is the change from 8 to 6?
These are my answer choices. I've worked the problem and I can't get any of them.
-2
ok, so if we call 8 \(a_0\) that makes six, \(a_1\)
so we first have 8-2
now how to go from 8 to 4?
Oh okay, that makes sense. I was making 8 a1 instead of a0.
well, the last answer works for 8 being a_1
and the first answer works for it being a_0
So with the first answer to get 4 we would do 8+ -2(3) = 2 so that wouldn't be correct?
well with the first answer 4 is a_2
with the last, 4 is a_3
Okay so that would make it 8 + -2(2) = 4 for the first?
yea, and the last works if you start with 8=a_1.
So that would make the last one the answer then? Do you have to start with 8 = a1?
no, they start both ways, so it depends on how you define your sequences in class. Do you start with a0 or a1?
a1 I believe.
alright, so, plug in n=1 make sure you get 8, n=2 make sure you get 6 etc. which eq. satisfies this?
although I would argue with the teacher if you get it incorrect. They did not specify which to begin with.
8 + -2(1-1) = 8 8 + -2(1-2) = 6 8 + -2(3-1) = 4
So would that mean the last one is correct? Also, it's for an online class and it usually isn't always specific which makes things difficult.
I would think so. And online classes do suck for this.
Yeah it does. Thank you for all your help though and for replying so quick!
I think most start the sequence with a1, so I'm like 95% confident. np best of luck
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