am I right? (Alg 2) ( I award medals and maybe a testimonial :)) 3^-3*3^4*3^2=27^3

Question

study_buddy99 · Answer

yay, thank you!

zarkon · Answer

you don't multiply the bases

zarkon · Answer

$$\Huge3^{-3}\times3^{4}\times3^{2}=3^{-3+4+2}=3^{3}$$

zarkon · Answer

$$3^{-3}\times3^{4}\times3^{2}=\frac{1}{3}\frac{1}{3}\frac{1}{3}3\cdot3\cdot3\cdot3\cdot3\cdot3$$

zarkon · Answer

$$=\frac{1}{\cancel{3}}\frac{1}{\cancel{3}}\frac{1}{\cancel{3}}\cancel{3}\cdot\cancel{3}\cdot\cancel{3}\cdot3\cdot3\cdot3$$

$$=3^3$$

563blackghost · Answer

O,o Excuse me, I must now go back and study multiplying exponents with common bases....

study_buddy99 · Answer

according to mathway @563blackghost you're right

563blackghost · Answer

@Zarkon is correct....

His simplification $\Large{3^{3}=27}$ so Zarkon is correct...

study_buddy99 · Answer

but... 3^3 is equal to 27 but 27 is in simplist form

study_buddy99 · Answer

so wouldn't the answer be 27

563blackghost · Answer

Yes it would be $\LARGE{27}$ but when I solved it I had put up $\LARGE{27^{3}}$ which is incorrect...

study_buddy99 · Answer

oh!

563blackghost · Answer

yup

study_buddy99 · Answer

but what if they were to have different bases?