PLEASE HELP!! i keep figuring this out but im kind of confused 1. Calculate the number that you need to add to each side of the equation w^2 - 3w = 350 to create a perfect square trinomial. 2. Factor the trinomial. 3. Now that you've factored the equation, find the square root of each side and solve for w.
It's completing the square, is it not?
For completing the square problems, always start out with generic square and multiplying it:\[ (x+s)^2=x^2+2sx+s^2 \]The term we will add to both sides is \(s^2\). Now if we have an equation: \[ x^2+bx+c \]We can say \(b=2s\) and thus \(s^2 = (b/2)^2\). We add \((b/2)^2\) to both sides.
You've provided an equation where \(b=-3\), so we need to add \((-3/2)^2=9/4\) to both sides.
Well, you can just memorize the \((b/2)^2\) term, but multiplying a generic square allows you to derive it rather quickly.
@wio i got this w^2-3w=350 w^2-3w +(-3/2)^2=350 w^2-3w +(9/4) =350 +(9/4)
Now remember that \(s=-3/2\), so that means:\[ w^2-3w+(9/4) = (w-3/2)^2 \]
This comes from our equation \[ x^2+2s+s^2=(x+s)^2 \]but we use \(w\) instead of \(x\).
If we take the square root of both sides, we get: \[ |w-3/2| = \sqrt{350+9/4} \]Which means \[ w = -3/2\pm \sqrt{350+9/4} \]You should simplify the square root though.
dont u have to square the -3/2
No, why would you need to square it?
@wio i got this w^2 - 3/2 = square root of 352.25
What should i do nxt??
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