Question

The slope of the line below is -1. Write the point slope equation of the line using the coordinates of the labeled point (7,-7)

Answer 1

Point-Slope Form:

\(\sf y - y_1 = m(x - x_1)\)

Where \(\sf y_1\) is the y-value of the point, \(\sf x_1\) is the x-value of the point, and \(\sf m\) is the slope.

Can you plug the numbers in?

Answer 2

okay so i did
y-y1=m(x-x1)
y-(7)=(-1)(x-(-7)
y-7=-1(x+7)
y-7=-1x+(-7)
y=-1x+-7-7
y=-1x-0
im not sure if i did this correctly

Answer 3

is that right or no @iGreen

Answer 4

Not quite..you got 'x' and 'y' mixed up.

(7, -7)
x1 y1

Answer 5

Try again

Answer 6

Okay so i redid it
y-y1=m(x-x1)
y-(-7)=(-1)(x-7)
Y+7=-1(x-7)
Y=7=-1x-(-7)
y=-1x+7-7
Y=-1x+0
I got the same thing i think im doing something wrong @igreen

Answer 7

No..remember, they're only asking for the answer in point-slope form..there's no need to convert it to slope intercept form.

y+7=-1(x-7) is correct

Answer 8

ohhhh now i get it lol thank you im not the best at math lol

Answer 9

can i ask you how to do one thing ?

Answer 10

Yes

Answer 11

I have a question that asks how to find the point of a line described by an equation
y-8=-3(x-6)
how do i do that im not asking for the answer i wanna know how to do that

Answer 12

That equation is in point-slope form. And remember the definition of point-slope form.

\(\sf y - y_1 = m(x - x_1)\)

Where \(\sf y_1\) is the y-value of the point, \(\sf x_1\) is the x-value of the point, and \(\sf m\) is the slope.

So what's the point in that equation?

Answer 13

(6,8) ??

Answer 14

and the slope is -3?

Answer 15

@iGreen

Answer 16

Yep, you got it.