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Mathematics 18 Online
OpenStudy (anonymous):

One model of Earth's population growth is Here's a picture http://media.apexlearning.com/Math/200706/06/38abe12b-e995-42fa-932c-e5e200104cd7.gif A. The population of Earth will grow exponentially for a while but then start to slow down its growth. B. In 1990, there were 5.33 billion people. C. The carrying capacity of Earth is 5.33 billion people. D. The population of Earth is increasing by a steady rate of 8% per year. I'm thinking the answer's are A and B but I'm not sure! please help me understand

zepdrix (zepdrix):

We can have multiple correct answers on this one?

OpenStudy (anonymous):

yes!

OpenStudy (faiqraees):

You can work out B and C right?

OpenStudy (anonymous):

im not sure

OpenStudy (anonymous):

it could also be answer D. im confused

OpenStudy (faiqraees):

Set t= 1990 and work out the value of population. If it is 5.33 billion then b is correct

OpenStudy (faiqraees):

Wait a minute is the value of t is going to directly have the numerical value of year or is it going to go through some process?

OpenStudy (faiqraees):

Can you send the whole question if possible?

OpenStudy (anonymous):

I'm so sorry I forgot there was more to this question! measured in years since 1990, and P is measured in billions of people. Which of the following statements are true

OpenStudy (faiqraees):

Okay so set the value of t = 0 and then work out the value of function. If the answer is 5.33 then B is correct

OpenStudy (anonymous):

which other answer is correct?

OpenStudy (faiqraees):

Can C be correct?

OpenStudy (anonymous):

im not sure lol this is so hard for me

OpenStudy (faiqraees):

The carrying capacity of Earth is 5.33 billion people. Set an equality \[\large\rm \frac{64}{1+11e^{0.08t}} >5.33\] Work ou the value of t. If it is positive then the statement is true.

OpenStudy (anonymous):

i got t<0.00852515 is that positive?

OpenStudy (ineedhelplz):

(b) and (c) for b: set t=0 (year 1990) you will get 5.33 (pop in billions in 1990) for c: for rel. small t the exp function dominates the denominator. Since it has negative power you can view it as exponential in the numerator and hence the growth can be called approximately exponential. As t gets larger this this trend attenuates and the growth becomes flat. (whic, btw., makes the statement (d) incorrect!)

OpenStudy (anonymous):

so b and c are the correct answers?

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (faiqraees):

Are you sure you solved the equation correctly?

OpenStudy (anonymous):

probably not :( ugggggh sorry for being difficult

OpenStudy (faiqraees):

Well then c is correct

OpenStudy (ineedhelplz):

B and C are correct....

OpenStudy (faiqraees):

D is wrong since its a curve so a constant gradient/ slope cant be achieved since rate refers to gradient

OpenStudy (faiqraees):

For A equate the derivative to 0, if equation satisfies than a is also correct

OpenStudy (anonymous):

i dont think A is correct

OpenStudy (anonymous):

so b and c?

OpenStudy (faiqraees):

Yeah

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