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Mathematics 12 Online
OpenStudy (anonymous):

The thickness of a kersone spill is 1.2 mm. The spill is .79 miles in diameter. Kerosene has a density of .82g/cc. Assumind that the spill is uniform in thickness and is shaped in a circle, how much kerosene, volume and mass is spilled? Give volume in gallons and mass in tons.

umerlodhi (umerlodhi):

what do you think m8

OpenStudy (anonymous):

Well I have the answers. For the volume I think it would be .58 grams and the mass would be .48 @umerlodhi

OpenStudy (anonymous):

I got this using the formula \[v = \pi r^{2} h\]

OpenStudy (anonymous):

So it would be \[v = 3.14 (.395)^2 (1.2)\]

OpenStudy (anonymous):

because the h, is the thickness, so it is 1.2

OpenStudy (anonymous):

@umerlodhi Am I right? and if I am, how would I change my answers to gallons and tons?

OpenStudy (agent0smith):

You can't use miles and mm in the same volume formula. You need to use the same units.

OpenStudy (anonymous):

Well the diameter is in miles and the thickness in mm

OpenStudy (anonymous):

How could I make them the same unites?

OpenStudy (anonymous):

units*. Would I use the factor-label method?

OpenStudy (anonymous):

Are the answers I got for the volume and mass correct though? Like the method I used?

OpenStudy (agent0smith):

I don't know what you've learned about unit conversions, but I'd convert them both to whatever units make converting to gallons easier. Or go with cm, because the density is in g/cm^3. Your answers are nonsensical, because you used two different units to find the volume.

OpenStudy (anonymous):

um ok... Do you think you could help me? Like walk me through it and I answer?

OpenStudy (anonymous):

I could probably do the whole converions bit if I had some help.. I tend to mess the whole thing up usually, specially when it comes to the factor-label method.

OpenStudy (anonymous):

Like, what units do you suggest I use?

OpenStudy (agent0smith):

I don't know what the factor-label method is. I don't even know what units to suggest, because I've never needed to convert volume to gallons. This question would be really easy if not for the awful units. Looks like you already know how to get the volume. Just use google or use your notes and see what you have for converting cm^3 to gallons, or m^3 to gallons, or liters to gallons, or something.

OpenStudy (anonymous):

so convert the volume (which is in miles) to centimeters, and then covert the cm to gallons?

OpenStudy (agent0smith):

You can't convert the volume now, that'd be much harder. You have to convert the units BEFORE finding the volume. mm to cm is easy, divide by 10. Miles to cm you might want to google. Or use your notes to convert miles to km then to cm.

OpenStudy (anonymous):

And how about the mass? Since the volume is wrong, does that mean the mass is wrong too?

OpenStudy (agent0smith):

Everything you did is wrong, sorry. You can't multiply two different units, as the result won't make any sense. You have to start from scratch. Convert both to cm first.

OpenStudy (anonymous):

Both what?

OpenStudy (agent0smith):

Thickness and radius.

OpenStudy (anonymous):

Ok. So convert both of them to cm?

OpenStudy (agent0smith):

Yes. Then your volume will be in cm^3.

OpenStudy (anonymous):

Ok.. Can i work on it and then call you back when I get my answer?

OpenStudy (anonymous):

Wait one more thing. Is teh formula for volume correct? Is that the right formula to use?

OpenStudy (agent0smith):

Yes, V = pi*r^2*h I gotta leave. Either use your notes to convert, or google miles to cm And cm^3 to gallons. For the mass, multiply the density .82g/cc by the volume (in cm^3, not gallons). That'll give you mass in grams. Then I guess google grams to tons

OpenStudy (anonymous):

ok, thank you for all your help!

OpenStudy (agent0smith):

Oh and mm to cm is easy, divide by 10. This question is an excellent example of why imperial units are terrible. What a clusterf--- of conversions.

OpenStudy (anonymous):

I agree

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