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Find the limit of the function by using direct substitution. limit as x approaches three of quantity x squared plus eight x minus two.
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\[\lim_{x \rightarrow 3}(x^{2} + 8x - 2)\]
\[\large\rm \lim_{x \rightarrow 3} ~~~x^2+8x-2\] like this ??
ohh okay cool. *direct substitution* just substitute x for 3 and then solve. that's it.
\[\lim_{x \rightarrow \frac{ \pi }{ 2 }}(2e ^{x}\sin x)\]
i have to use direct substitution for this one as well
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alright same steps when the direction is *direct substitution * then just substitute x for the number its approaches by
\[(2e ^{\left(\begin{matrix}\pi \\ 2\end{matrix}\right)} \sin \frac{ \pi }{ 2 })\]
how do i solve from there?
sin (pi/2) = ??? you can use unit circle.
equals 0
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