Suppose you just received a shipment of twelve televisions. Two of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?
@ganeshie8
I keep getting stupid answers and it's really irritating me.
We are given that 2 tvs are defect out of 12 tvs. This means, P(good) = 10/12 P(bad) = 2/12
So.... I'd divide 2/12 right?
Lets do it like this
You pick one tv first. Whats the probability for it to be good ?
Number of good tvs = 10 Total number of tvs = 12 P(good) = 10/12 right?
After picking one tv, there will be 11 more tvs. Out of them, 9 tvs are good and 2 tvs are bad. So for picking a good tv the second time also, the probability would be : P("good second time") = 9/11 yes ?
Therefore, P("good both times") = 10/12 * 9/11 = 15/22
see if that makes any sense...
see if that makes any sense...
Okay, yes that does make sense. I was doing 2/12 and other crazy fractions that I don't know... But yes, that definitely makes sense. Great explanation!! Thanks. Switch brains with me please lol
Haha ikr, probability is a bit confusing in the start... But it helps if we take time to understand the problem thoroughly before attempting the solution..
Look at second part of the question
`What is the probability at least one of the two televisions does not work?`
So wait, it would be 15/22?
`. If two televisions are randomly selected, compute the probability that both televisions work.` 15/22 is the answer to this part of the problem
we still need to work the second part of the problem
I think I know this one.
I'd have: 1-0.682 Right?
Nevermind I got it.
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