Stats anyone? Due to a manufacturing error, five cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppose that two cans are randomly selected from the 18-pack. Complete parts (a) through (c). @kropot72
Part C asks: (c) Determine the probability that exactly one is diet and exactly one is regular. I got a wrong answer and I don't know what I'm doing wrong. Please help.
Don't forget there's two cases: first is diet, second is regular and first is regular, second is diet. For the first case: Chance of diet first is 5/18, then the regular second is 13/17. Multiply those to get the probability for the first case.
Second case: Chance of regular first is 13/18, chance of diet second is 5/17. Multiply those for the probability for the second case. Then add the probabilities for the first and second case.
Idk if you follow or not. But there's 18 total sodas, 5 diet sodas, so 13 regular sodas. Once you've taken out one can, the total goes down to 17.
Yes, I'm following. So that's what I'd do for Part C?
Yes.
So I would add 13/17+5/18?
For the first case: Chance of diet first is 5/18, then the regular second is 13/17. Multiply those. Second case: Chance of regular first is 13/18, chance of diet second is 5/17. Multiply those. Add the results of the first and second cases.
Thanks!!
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