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Mathematics 14 Online
OpenStudy (yanasidlinskiy):

Stats anyone? Due to a manufacturing​ error, five cans of regular soda were accidentally filled with diet soda and placed into a 18​-pack. Suppose that two cans are randomly selected from the 18​-pack. Complete parts​ (a) through​ (c). @kropot72

OpenStudy (yanasidlinskiy):

Part C asks: ​(c) Determine the probability that exactly one is diet and exactly one is regular. I got a wrong answer and I don't know what I'm doing wrong. Please help.

OpenStudy (agent0smith):

Don't forget there's two cases: first is diet, second is regular and first is regular, second is diet. For the first case: Chance of diet first is 5/18, then the regular second is 13/17. Multiply those to get the probability for the first case.

OpenStudy (agent0smith):

Second case: Chance of regular first is 13/18, chance of diet second is 5/17. Multiply those for the probability for the second case. Then add the probabilities for the first and second case.

OpenStudy (agent0smith):

Idk if you follow or not. But there's 18 total sodas, 5 diet sodas, so 13 regular sodas. Once you've taken out one can, the total goes down to 17.

OpenStudy (yanasidlinskiy):

Yes, I'm following. So that's what I'd do for Part C?

OpenStudy (agent0smith):

Yes.

OpenStudy (yanasidlinskiy):

So I would add 13/17+5/18?

OpenStudy (agent0smith):

For the first case: Chance of diet first is 5/18, then the regular second is 13/17. Multiply those. Second case: Chance of regular first is 13/18, chance of diet second is 5/17. Multiply those. Add the results of the first and second cases.

OpenStudy (yanasidlinskiy):

Thanks!!

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