Can someone please show me how to solve this?

Question

ms-brains · Answer

attachment

theprofessor35 · Answer

Quadratic variation 

y = kx^2

ms-brains · Answer

Yeah..and?

ms-brains · Answer

Why? Can someone explain how to solve this..and not give me a direct answer?

im_an_angel · Answer

sure i can try :)

theprofessor35 · Answer

Hold on, i need to draw this out visually in my head.

theprofessor35 · Answer

Been such a long time since I've reviewed variation.

im_an_angel · Answer

so your chart shows the x-y values 2/28 im pretty sure you just reduce giving you 1/14

theprofessor35 · Answer

K would always represent the constant of variation in y = kx^2 

So....

im_an_angel · Answer

you're already better at explaining this, im gonna give you a medal lol @TheProfessor35

theprofessor35 · Answer

Awww, I'm gonna medal you back. :P
@im_an_angel

im_an_angel · Answer

thx :) @TheProfessor35

ms-brains · Answer

So you guys are sure it's 14?

theprofessor35 · Answer

I'm not sure of the final answer, although I just known a bit of some general info on this...not too sure I could solve it though. Sorry.

ms-brains · Answer

Okay. well you two were no help.

ms-brains · Answer

Anyone else know to solve this?

anonymous · Answer

f(x)=kx^2

k is the constant and can be found by transforming the equation
k=f(x) divided by x^2

anonymous · Answer

Understand? I can help you work it out if necessary

fortytherapper · Answer

I agree with the other two

Using f(x) = kx^2

Plugging in the first option, we get 28 = x(2^2), because f(x) is 28 and x is 2

2^2 = 4, which means 28 = 4(x). Divide by 4 on each sides, and what would x be?

You can try that out for the others and if you get the same result for each, that's your variation.

im_an_angel · Answer

ha i wasnt so useless after all apparently