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Mathematics 18 Online
OpenStudy (study_buddy99):

help me graph pretty pretty please with medals on top?!

OpenStudy (study_buddy99):

\[2\sqrt{x+4}-3\] I don't understand how to get coordinates?

OpenStudy (fortytherapper):

\[(x, y) \] is your basic coordinate and the equation is \[y= 2\sqrt{x+4}-3\] So plug in x values to get corresponding y values. Knowing the general shape of the squarer root function will help at the end. I would pick x values that make a perfect square root. For example, if you make x = 5 \[y = 2\sqrt{(5) +4}-3\] 5 + 4 = 9, which makes it easy because the square root of 9 is 3. So 2 times the square root of 9 is the same as 2 times 3, which is 6. Then 6 minus 3 = 3. Making the coordinate (5, 3)

OpenStudy (study_buddy99):

ah I see, I got stuck right before getting to the 3

OpenStudy (study_buddy99):

\[-\sqrt[3]{x+1}+5\]

Directrix (directrix):

Tip of the Day ------------- What you posted is an algebraic expression. Always write f(x)= or y = the expression when you're talking equations.

OpenStudy (study_buddy99):

I keep forgetting (>.<) oops it's f(x)

Directrix (directrix):

This is such a cool calculator. You'll get to try it next. It is easy to zoom in and out, click on the graph and get point coordinates and all that.

OpenStudy (fortytherapper):

Remember that the small number above the square root can be rewritten as the denominator of the fraction For example \[\sqrt[5]{x-3} = (x-3)^{1/5} \]

Directrix (directrix):

Whoops! I did not use 3 as the index. Hold on.

Directrix (directrix):

Interesting that the graph crosses the x-axis and is very slowly moving away.

Directrix (directrix):

Questions or observations about the graph? @study_buddy99

OpenStudy (study_buddy99):

I got it

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