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Mathematics 11 Online
OpenStudy (anonymous):

The standard normal curve shown below models the population distribution of a random variable. What proportion of the values in the population does not lie between the two z-scores indicated on the diagram?

OpenStudy (anonymous):

heres the picture

OpenStudy (anonymous):

Ahhh I'm not sure how to do the problem. Sorry hun!!

OpenStudy (agent0smith):

You'll have to use a calculator, or a table of z-values, to find \[\large P(-1.25<z<0.80) =\]

OpenStudy (anonymous):

i have no idea how you got that..

OpenStudy (agent0smith):

If you use a z-table, you might need to do it like so\[\large P(-1.25<z<0.80) = \] \[\large P(z<0.80)-P(z<-1.25)\]

OpenStudy (agent0smith):

The values given on the graph are z-scores. You need to first find the area between those two z-scores, which is what I gave you. Once you have that, then you subtract that area from 1, to find the area outside the shaded region.

OpenStudy (agent0smith):

So, the thing you need to actually find is this \[\large 1-P(-1.25<z<0.80) =\]

OpenStudy (anonymous):

that doesnt make sense to me

OpenStudy (michele_laino):

from my tables of statistics, I get these results: \[\Large \begin{gathered} P > 0.8 = 0.2119 \hfill \\ \hfill \\ P < - 1.25 = 0.1056 \hfill \\ \end{gathered} \]

OpenStudy (michele_laino):

so the requested probability, is: \(0.2119+0.1056=...?\)

OpenStudy (anonymous):

0.3175?

OpenStudy (michele_laino):

that's right!

OpenStudy (agent0smith):

@Michele_Laino if nothing I wrote made sense to her, then nothing you gave her will help her understand.

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