Question

A bag of 30 tulip bulbs contains 14 red tulip​ bulbs, 9 yellow tulip​ bulbs, and 7 purple tulip bulbs. What is the probability that one bulb is red and the other​ yellow?

Answer 1

your thoughts?

Answer 2

I have no idea honestly.

Answer 3

Any information about replacement given?

2 bulbs are taken one after another or,
1 bulb is taken, put back, and then again one more bulb is taken?

Answer 4

Well, I've already figured those out this is just the last part of the question.

Answer 5

its not the entire question? can you post entire q?

Answer 6

Yes.
(a) What is the probability that two randomly selected tulip bulbs are both​ red?
​(b) What is the probability that the first bulb selected is red and the second​ yellow?
​(c) What is the probability that the first bulb selected is yellow and the second​ red?
​(d) What is the probability that one bulb is red and the other​ yellow?

Answer 7

so (d) is very similar to (b)
how did you solve for b?

Answer 8

and (c)

infact, (d) = (b) + (c) :P

Answer 9

one bulb red and other yellow = 1st red, 2nd yellow OR 1st yellow, 2nd red

Answer 10

Lol I see. And well, I did 14/30 * 9/29 And Got, 0.145

Answer 11

yep ! you are going right .
But it is one case

Answer 12

so it is without replacement!

Answer 13

if you understand this:
one bulb red and other yellow = 1st red, 2nd yellow OR 1st yellow, 2nd red

it will be obvious to you why we just add b and c for d :)

Answer 14

Since this is MUTUALLY EXCLUSIVE ELEMENTS.
So,
\[\large \bf P(A~or~B)=P(A)+P(B)\]

Answer 15

There are 2 cases now

Answer 16

Case 1 :-
When you pick first RED and then YELLOW
Case 2 :-
When you pick first YELLOW and then RED

Answer 17

you have done CASE 1 so far

Answer 18

now solve for CASE 2 and then add them

Answer 19

So would it be:
9/30*14/29?

Answer 20

correct

Answer 21

and then add them

Answer 22

One second. Lemme see what I get.

Answer 23

wait wait !

Answer 24

i'm wrong

Answer 25

i misread the question

Answer 26

there is `and` not `or`

Answer 27

mayank, we all are on right track

Answer 28

don't get confused :P

Answer 29

nope

Answer 30

Sooo.....

Answer 31

there is a difference between
ONE IS RED OR YELLOW
and
ONE IS RED AND YELLOW

Answer 32

one bulb red and other yellow = 1st red, 2nd yellow OR 1st yellow, 2nd red

Answer 33

which was what we were doing

Answer 34

okay !

Answer 35

sorry ! @YanaSidlinskiy i was confused

Answer 36

So, was I right then?

Answer 37

yep

Answer 38

It's alright hahha we all make mistakes.

Answer 39

add them

Answer 40

yes,
go on

Answer 41

@hartnn i have a doubt

Answer 42

when we use this equation :-
\[\large \bf P(A~and~B)=P(A) P(B|A)\]

Answer 43

since they are DEPENDENT EVENTS

Answer 44

Well, technically yes, I am supposed to use that formula but it does confuse me. Just as Hartnn said, we add B AND C to get D and that's exactly what I did and came out to 0.29 which is right. Thanks for all the help to the both of you:) Statistics is just really hard. Practice=perfect almost and mayan don't get confused too much hahha.

Answer 45

i got now !

Answer 46

Thank you :)

Answer 47

Youre Welcome.