Statistics help please?
Suppose you just received a shipment of ten televisions. Three of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?

Question

Statistics help please? 
Suppose you just received a shipment of ten televisions. Three of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?

anonymous · Answer

1 / 2 = 0.5 = 50%

yanasidlinskiy · Answer

It'd be great if you provided an explanation:)

hartnn · Answer

3 defective , 7 work.

the 2 selected computers should be from these 7 working ones.

yanasidlinskiy · Answer

So, I'd subtract 2 from 7 then?

anonymous · Answer

For selecting one working one, you would have probability $7/10$. Once you remove it, you will have $3$ defective and $6$ working. So for the probability of the second working one, you have $6/9$. These events are independent, because the second event is conditional on the first one, so you can find the whole probability by multiplying them.

yanasidlinskiy · Answer

I got .467 is that right?