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Mathematics 15 Online
OpenStudy (thecalchater):

Check my Calculus work?

OpenStudy (thecalchater):

hey zeppy.

zepdrix (zepdrix):

Number 1 looks no bueno

zepdrix (zepdrix):

none of the options for (1) look correct.. hmmmmm

zepdrix (zepdrix):

The 8 should be an exponent when it comes into the log

zepdrix (zepdrix):

Ya problem A doesn't have a correct option, I'm pretty sure... You'll have to ask teacher, I think he made a boo boo

zepdrix (zepdrix):

#2 looks good!

zepdrix (zepdrix):

#4 looks great!

zepdrix (zepdrix):

Explain that the 8 should be an exponent on the (x^2+6), not a coefficient :)

zepdrix (zepdrix):

#5 looks bueno!

OpenStudy (thecalchater):

Numero tres no bueno XD

zepdrix (zepdrix):

Oh that one is just a derivative? :D fun fun fun

zepdrix (zepdrix):

\[\large\rm y=\ln\left(x\sqrt{x^2+15}\right)\]

OpenStudy (mathmath333):

try \(\log x+\log\sqrt{x^{2}+15}\)

zepdrix (zepdrix):

Oh true true, log rule first might be helpful

zepdrix (zepdrix):

\[\large\rm y=\ln(x)+\ln\left(\sqrt{x^2+15}\right)\]

zepdrix (zepdrix):

\[\large\rm y'=\frac{1}{x}+\frac{1}{\sqrt{x^2+6}}(\sqrt{x^2+6})'\]Something like this? :o

zepdrix (zepdrix):

Mmm I don't understand. You need to use more brackets maybe. I can't tell what belongs to what.

OpenStudy (mathmath333):

u can take like this \(\large\rm y=\ln(x)+\dfrac12\ln\left(x^2+15\right)\)

OpenStudy (mathmath333):

apply chain rule on \(\dfrac12\ln\left(x^2+15\right)\)

OpenStudy (mathmath333):

thats correct

OpenStudy (mathmath333):

u get this x/x^2+15 ?

OpenStudy (mathmath333):

yep

OpenStudy (thecalchater):

thz guys :)

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