Mathematics
15 Online
OpenStudy (thecalchater):
Check my Calculus work?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (thecalchater):
hey zeppy.
zepdrix (zepdrix):
Number 1 looks no bueno
zepdrix (zepdrix):
none of the options for (1) look correct.. hmmmmm
zepdrix (zepdrix):
The 8 should be an exponent when it comes into the log
zepdrix (zepdrix):
Ya problem A doesn't have a correct option,
I'm pretty sure...
You'll have to ask teacher, I think he made a boo boo
Join the QuestionCove community and study together with friends!
Sign Up
zepdrix (zepdrix):
#2 looks good!
zepdrix (zepdrix):
#4 looks great!
zepdrix (zepdrix):
Explain that the 8 should be an exponent on the (x^2+6),
not a coefficient :)
zepdrix (zepdrix):
#5 looks bueno!
OpenStudy (thecalchater):
Numero tres no bueno XD
Join the QuestionCove community and study together with friends!
Sign Up
zepdrix (zepdrix):
Oh that one is just a derivative? :D
fun fun fun
zepdrix (zepdrix):
\[\large\rm y=\ln\left(x\sqrt{x^2+15}\right)\]
OpenStudy (mathmath333):
try \(\log x+\log\sqrt{x^{2}+15}\)
zepdrix (zepdrix):
Oh true true, log rule first might be helpful
zepdrix (zepdrix):
\[\large\rm y=\ln(x)+\ln\left(\sqrt{x^2+15}\right)\]
Join the QuestionCove community and study together with friends!
Sign Up
zepdrix (zepdrix):
\[\large\rm y'=\frac{1}{x}+\frac{1}{\sqrt{x^2+6}}(\sqrt{x^2+6})'\]Something like this? :o
zepdrix (zepdrix):
Mmm I don't understand.
You need to use more brackets maybe.
I can't tell what belongs to what.
OpenStudy (mathmath333):
u can take like this
\(\large\rm y=\ln(x)+\dfrac12\ln\left(x^2+15\right)\)
OpenStudy (mathmath333):
apply chain rule on
\(\dfrac12\ln\left(x^2+15\right)\)
OpenStudy (mathmath333):
thats correct
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mathmath333):
u get this
x/x^2+15 ?
OpenStudy (mathmath333):
yep
OpenStudy (thecalchater):
thz guys :)