. Suppose the population of deer in a region was 3500 in the year 2000. Since then the population has grown by 3.5% annually. What will the approximate population be in the year 2020?

Question

.  Suppose the population of  deer in a region was 3500 in the year 2000.  Since then the population has grown by 3.5% annually.  What will the approximate population be in the year 2020?

sam141101 · Answer

sorry idk but hope you figure it out welcome to open study btw :)

bruh747 · Answer

its cool thnks

sam141101 · Answer

np :)

qwertty123 · Answer

Hey! WELCOME! :D Okay lets see here..

qwertty123 · Answer

We can use the formula for exponential growth: 

y=a(1+b)^x
Y is the answer to your question. 

A is the starting population of deer. 
(In this case, we would 3500.) 

B is the percent change, in decimal form.
(If the deer grow 3.5% every year, 
then the decimal form would be 0.035.) 

X is the amount of time passed. 
(In this case, that would be 20 years, 
because that's how long it is, from 2000 to 2020.)

bruh747 · Answer

is it 5950?

rebeccaxhawaii · Answer

hold on lemme plug it in

mathmale · Answer

@bruh:  rather than ask, "Is it 5950?" please share your own calculations.  Might get better feedback that way.

mathmale · Answer

@bruh747:  Note that the formula Qwertty has suggested is correct, and is the same one (save for variable names) as is used to find the Amount when a beginning Principal earns interest at a certain interest rate, compounded annually, for t years or n payment periods.

bruh747 · Answer

when i pluged it in and added 1+0.035
i got 6965(rounded)
what do you think?

mathmale · Answer

Please use qwertty's formula:   y=a(1+b)^x

Show all numbers that you choose to "plug in."