Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

The yellow dot is what i think the y-intercept is? Is that correct? Also, how do i find the slope

OpenStudy (anonymous):

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

@mathmale

OpenStudy (jdoe0001):

well, to find the slope, pick any two points from the "best fit line" first any two points on it :)

OpenStudy (anonymous):

@jdoe0001 is this good ?

OpenStudy (anonymous):

OpenStudy (jdoe0001):

yes if I read those two points correctly, those will be 0,0 and 17.5,7 so, to get the slope of that line that goes through (0,0) and (17.5, 7) \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}})\quad % (c,d) &({\color{red}{ 17.5}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

OpenStudy (jdoe0001):

actually, dohh, hold the mayo. got those fractions a bit off

OpenStudy (jdoe0001):

hmmm

OpenStudy (jdoe0001):

should be rise/run... lemme fix that quick

OpenStudy (jdoe0001):

that is 7/17.5

OpenStudy (anonymous):

so

OpenStudy (jdoe0001):

so, that'd be the slope of the "best fit line"

OpenStudy (anonymous):

OpenStudy (anonymous):

Is that good ? @jdoe0001

OpenStudy (jdoe0001):

slope is just a scalar value, just a number not a coordinate so... you could use \(7\div 17.5\) or use the fraction above of 14/35 :)

OpenStudy (jdoe0001):

lemme fix my typo there which in short.. will just be \(\bf \Large \cfrac{7}{ 17.5}\) =) anyway or to put in rational \(\bf \cfrac{7}{\frac{35}{2}}\implies \cfrac{7}{1}\cdot \cfrac{2}{35}\implies \cfrac{14}{35}\impliedby \cfrac{rise}{run}\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!