The yellow dot is what i think the y-intercept is? Is that correct? Also, how do i find the slope
@jdoe0001
@mathmale
well, to find the slope, pick any two points from the "best fit line" first any two points on it :)
@jdoe0001 is this good ?
yes if I read those two points correctly, those will be 0,0 and 17.5,7 so, to get the slope of that line that goes through (0,0) and (17.5, 7) \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}})\quad % (c,d) &({\color{red}{ 17.5}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)
actually, dohh, hold the mayo. got those fractions a bit off
hmmm
should be rise/run... lemme fix that quick
that is 7/17.5
so
so, that'd be the slope of the "best fit line"
Is that good ? @jdoe0001
slope is just a scalar value, just a number not a coordinate so... you could use \(7\div 17.5\) or use the fraction above of 14/35 :)
lemme fix my typo there which in short.. will just be \(\bf \Large \cfrac{7}{ 17.5}\) =) anyway or to put in rational \(\bf \cfrac{7}{\frac{35}{2}}\implies \cfrac{7}{1}\cdot \cfrac{2}{35}\implies \cfrac{14}{35}\impliedby \cfrac{rise}{run}\)
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