Question

1117, 1465, 513, 437, 1038, 954, 650, 893, 456, 1018

Answer 1

@Directrix

Answer 2

find the range, median, first and third quartiles, and interquartile

Answer 3

@Directrix

Answer 4

First thing, write the data points in increasing order.

Answer 5

437, 456, 513, 650, 893, 954, 1018, 1038, 1117

Answer 6

I think that one of the data points is missing. There are ten posted in the problem and only nine in the ascending order list.

Answer 7

1465 at the end i forget

Answer 8

437, 456, 513, 650, 893, 954, 1018, 1038, 1117, 1465

Answer 9

I am well aware of that online calculator. I don't know why this person is in the thread interrupting our work. We could have been finished by now.

Answer 10

@Directrix yes, i already know that website but because i don't understand it so i need help

Answer 11

i dont want to just copy the answer from website

Answer 12

i want to understand it

Answer 13

437, 456, 513, 650, 893, 954, 1018, 1038, 1117, 1465

@JessicaH123

Do you see that there are 10 data points in the set?

Ten is an even number and splitting the data set in half to get the median means that two numbers will be in the midde, the 893 and the 954.

Answer 14

To find the median, your numbers have to be listed in numerical order.

The "mode" is the value that occurs most often. If no number is repeated, then there is no mode for the list.

The "range" is just the difference between the largest and smallest values.

Answer 15

so the median is 923.5? @Directrix

Answer 16

437, 456, 513, 650, 893, 954, 1018, 1038, 1117, 1465

Take half the sum of 893 and 954 to get the median.

>>so the median is 923.5? Yes.

Answer 17

Finally, I can post.

Answer 18

ok what next?

Answer 19

@Directrix please help me

Answer 20

@Directrix where are you? please help me

Answer 21

@Directrix please help me!!!!!!!!!!!! T_T

Answer 22

What do you need?

Answer 23

I am trying to but if I post, then the screen freezes. After I refresh the page, then it takes 4 to 5 minutes before I can post. I will put as much as I can in this block.

First quartile:

923.5
437, 456, 513, 650, 893, 954, 1018, 1038, 1117, 1465

From the median Q2 to the left, there are 5 data entries.

437, 456, 513, 650, 893,

What is the median of those 5 elements? That will be Q1, the lower quartile.

Answer 24

513

Answer 25

Correct.

For the upper quartile, the same procedure:

954, 1018, 1038, 1117, 1465

What is the median of this group?

Answer 26

1038

Answer 27

Correct.

Answer 28

For the IQR, Q3 - Q1 = ?

Answer 29

525 @Directrix

Answer 30

Correct.

Answer 31

@JessicaH123

The one tricky thing in doing these types of problems is the number of elements in the data set and how that changes the median finding procedure.

Answer 32

thank you very much you save my life @Directrix

Answer 33

You are welcome. @JessicaH123
Sorry about the freeze-up delays.

Answer 34

it okay ^_^

Answer 35

bye