How much heat is required to raise the temperature of 80.0 g of water from its melting point to its boiling point? I have this equation set up right here m=80.0g, C=4.184J/(g⋅∘C), and ΔT=100∘C.

Question

baconboy73 · Answer

Now you need to plug it into the $$q = mC \Delta T$$ equation and get your answer for q in joules.

unklerhaukus · Answer

$$q \ \ = (80.0\ \text g)\left(4.184\ \frac{\text J}{\text g\ °\text C}\right)(100\ °\text C)\
\quad = (80.0\times4.184\times100) \frac{\cancel{\text g}\ \text J\ \cancel{°\text C}}{\cancel{\text g\ °\text C}}\
\quad = (80.0\times4.184\times100)\ \text J\
\quad =$$

anonymous · Answer

thanks