given: AC||BD, and AB||CD
Prove:
A) <PQC and <ACP are supplementary by the Linear Pair Theorem B) For parallel lines cut by a transversal, corresponding angles are congruent, so \[<ABC \approx<PCQ\] C)\[<OCP \approx<BCD\] by the vertical angle theorem D)For parallel lines cut by a transversal, corresponding angles are congruent, so \[ <OCP \approx<ABC\] E) For parellel lines cut by a transversal, corresponding angles are congruent, so \[<OCA \approx<CBD\]
got it?
no i dont v.v
@dan815
:(
tooo much to read
:( im sorry you dont gotta help
Id help, but I suck at proofs
its alright know anyone who is good at it?
id go with c
thanks :3
np anytime
the step right after the missing one says.. By the definition of congruent angle, m<OCP = m<ABC the missing congruency is probably relating those two angles
so what does that mean?
It is not stated in the proof yet that OCP is congruent to ABC, that is the missing step, they are corresponding angles C is true, but does not follow the proof
so its not the right answer? sorry im kinda getting confused
, D is the one
Ohh well thanks :3
welcome
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