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OpenStudy (ilovebmth1234):
A) <PQC and <ACP are supplementary by the Linear Pair Theorem
B) For parallel lines cut by a transversal, corresponding angles are congruent, so \[<ABC \approx<PCQ\]
C)\[<OCP \approx<BCD\] by the vertical angle theorem
D)For parallel lines cut by a transversal, corresponding angles are congruent, so \[ <OCP \approx<ABC\]
E) For parellel lines cut by a transversal, corresponding angles are congruent, so \[<OCA \approx<CBD\]
rebeccaxhawaii (rebeccaxhawaii):
got it?
OpenStudy (ilovebmth1234):
no i dont v.v
OpenStudy (ilovebmth1234):
@dan815
OpenStudy (dan815):
:(
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OpenStudy (dan815):
tooo much to read
OpenStudy (ilovebmth1234):
:( im sorry you dont gotta help
OpenStudy (anonymous):
Id help, but I suck at proofs
OpenStudy (ilovebmth1234):
its alright know anyone who is good at it?
OpenStudy (math_man21):
id go with c
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OpenStudy (ilovebmth1234):
thanks :3
OpenStudy (math_man21):
np anytime
OpenStudy (danjs):
the step right after the missing one says..
By the definition of congruent angle, m<OCP = m<ABC
the missing congruency is probably relating those two angles
OpenStudy (ilovebmth1234):
so what does that mean?
OpenStudy (danjs):
It is not stated in the proof yet that OCP is congruent to ABC, that is the missing step, they are corresponding angles
C is true, but does not follow the proof
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OpenStudy (ilovebmth1234):
so its not the right answer? sorry im kinda getting confused