Question

Rationalizing denominators: (cube root of x over cube root of y^-2)^9

Answer 1

The original expression was: \[\left( \frac{ x _{3}^{1}}{ y -_{3}^{2} } \right)^{9}\]

Answer 2

A negative exponent in the denominator is a positive exponent in the numerator.
A negative exponent in the numerator is a positive exponent in the denominator.