Question

i need help!

Answer 1

i need help!

Answer 2

@mathmale

Answer 3

@King.Void.

Answer 4

@DarryQX

Answer 5

help!

Answer 6

@mathmale @mathmath333

Answer 7

@hreeg97 @Taylor.Joe

Answer 8

we are not just going to do your homework for you! you have to ask specific problems

Answer 9

Multiplying Power w/ the Same Base: when you are multiplying, and the bases are the same,
you ADD the exponents.
e.g.,
\[ x^{2}+x^{3}=x^{2+3}=x^{5}\]

Power to a Power: To find a power of a power, multiply the exponents.
e.g.,
\[(x^{2})^{3}=x^{2\times3}=x^{6}\]

Quotient to a Power: When you raise a quotient to a power you raise both the numerator and the denominator to the power.
e.g.,
\[(\frac{ x }{ y })^{2}=(\frac{ x^{2} }{ y^{2} })\]

Exponent of Zero: Always equals 1
e.g.,
\[x^{0}=1\]

Negative Exponents: All I know about negative exponents is \[x^{-n}=\frac{ 1 }{ x^{n} }\], but this might help: https://www.khanacademy.org/math/pre-algebra/exponents-radicals/negative-exponents-tutorial/v/negative-exponents

Answer 10

@luvhawks711 - this should be able to help you with your homework. Good luck.

Answer 11

@SolomonZelman

Answer 12

@sweetburger

Answer 13

@Michele_Laino

Answer 14

@Zarkon

Answer 15

@ghgbf

Answer 16

@MissSmartiez

Answer 17

hint:
\[\huge {x^3} \cdot {x^5} = {x^{3 + 5}} = ...?\]

Answer 18

i need help with e) d) f) g) h)

Answer 19

question d)
for any quantity \(n\), I can write:
\[\huge {n^0} = 1\]

Answer 20

ok, e)

Answer 21

of course \(n \neq 0\)

Answer 22

yep

Answer 23

\[\huge \frac{{2{x^{ - 3}}y}}{{4{x^2}}} = \frac{2}{4} \cdot {x^{ - 3 - 2}} \cdot y = ...?\]

Answer 24

-6

Answer 25

hint:
we have:
\[\Large \frac{2}{4} = \frac{1}{2}\]
and:
\[\Large {x^{ - 3 - 2}} = {x^{ - 5}}\]

Answer 26

I got this:
\[\Large \frac{{2{x^{ - 3}}y}}{{4{x^2}}} = \frac{2}{4} \cdot {x^{ - 3 - 2}} \cdot y = \frac{1}{2}{x^{ - 5}}y\]

Answer 27

ok, f)

Answer 28

hint:
\[\huge \frac{{3{x^3}y}}{{4x{y^{ - 5}}}} = \frac{3}{4} \cdot {x^{3 - 1}} \cdot {y^{1 - \left( { - 5} \right)}} = ...?\]

Answer 29

please keep in mind that I have used this property:
\[\huge \frac{{{y^m}}}{{{y^n}}} = {y^{m - n}}\]

Answer 30

what is \(3-2=...?\)
and, what is \(1-(-5)=1+5=...?\)

Answer 31

h)

Answer 32

?

Answer 33

we can write this:
\[\Large {\left( {\frac{{5{x^2}}}{{3{y^3}}}} \right)^{ - 2}} = {\left( {\frac{5}{3}{x^2}{y^{ - 3}}} \right)^{ - 2}} = \frac{{{5^{ - 2}}}}{{{3^{ - 2}}}}{x^{2 \cdot \left( { - 2} \right)}}{y^{\left( { - 3} \right) \cdot \left( { - 2} \right)}} = ...?\]

Answer 34

\[\huge \begin{gathered}
{\left( {\frac{{5{x^2}}}{{3{y^3}}}} \right)^{ - 2}} = {\left( {\frac{5}{3}{x^2}{y^{ - 3}}} \right)^{ - 2}} = \hfill \\
\hfill \\
= \frac{{{5^{ - 2}}}}{{{3^{ - 2}}}}{x^{2 \cdot \left( { - 2} \right)}}{y^{\left( { - 3} \right) \cdot \left( { - 2} \right)}} = ...? \hfill \\
\end{gathered} \]

Answer 35

I have to distribute the outer exponent which is \(-2\)

Answer 36

ok

Answer 37

i need help with part 3 a and b

Answer 38

@freckles @Jintao.Andrew @TheCuteOne25
@edbf123 @Saylilbaby
@hansC