a carnival game has two boxes with 3 chips in one of the boxes, and 8 in the other. All the chips are numbered 1,2 or 3. A chip is randomly selected from each box to form a two-digit number. The first chip forms the tens' place digit, and the second chip forms the ones' place digit. For each example drawing a 1 and then a 3 forms the number 13, but not 31. The following probablities are possible: P(drawing 11)= 1/6
P(drawing 22)= 1/24
P(drawing 33)= 1/8
what is the probability of drawing a number greater than 22?

Question

a carnival game has two boxes with 3 chips in one of the boxes, and 8 in the other. All the chips are numbered 1,2 or 3. A chip is randomly selected from each box to form a two-digit number. The first chip forms the tens' place digit, and the second chip forms the ones' place digit. For each example drawing a 1 and then a 3 forms the number 13, but not 31. The following probablities are possible: P(drawing 11)= 1/6 
P(drawing 22)= 1/24 
P(drawing 33)= 1/8
 what is the probability of drawing a number greater than 22?

faiqraees · Answer

hey the 8 chips in the other box are also going to be 1,2,3? not 4,5,6 ...?

kropot72 · Answer

By the rules of probability, the box with 3 chips must have one marked 1, one marked 2 and one marked 3.

faiqraees · Answer

First you have to make a tree diagram to know the possible outcomes of each event. Then use the given probabilities to work out the probability of each outcome
|dw:1456372690564:dw|

faiqraees · Answer

We can find out the probability of the outcome of 1 when 1 is picked in the first box by dividing 1/6 by 1/3 which gives us 1/2|dw:1456372792039:dw|

faiqraees · Answer

Repeat the same thing for the other two and you have worked out the probability|dw:1456372828200:dw| of every outcome