Question

Will fan and medal!
A circle is described by the equation (x−1/2)^2+(y−3/2)^2=4/9. What are the cordinates for the center of the circle and the length of the radius?

Answer 1

\[\large\rm (x- \color{#0000ff}{ \displaystyle a})^2+(y-\color{#0000ff}{ \displaystyle b})^2=\color{#0000ff}{ \displaystyle r}^2\]
where (a,b) are the x and y coordinates of the center of the cirle and r is the radius of the circle

Answer 2

ok... so i just plug in the numbers with the equation??

Answer 3

Just find out the value of a and b

Answer 4

its 1/2 and 3/2 ?

Answer 5

yes

Answer 6

yes

Answer 7

oh okay what about the units?

Answer 8

no units

Answer 9

Well it has answer choices with different units.

(-1/2,-3/2), 23units

(-1/2,-3/2), 49units

(1/2,3/2), 49units

(1/2,3/2), 23units

it asks for units

Answer 10

oh units is for radius

Answer 11

Oh okay!!! thank you!!

Answer 12

(a, b)=(12 , 32 ), r=​23

Answer 13

Oh dang it was wrong :(

Answer 14

it was 23

Answer 15

(x−12 )2+(y−32 )2=49
(x−a)2+(y−b)2=r2 is the circle equation with a radius r, centered at (a, b)
$\left(x-\frac{1}{2}\right)^2+\left(y-\frac{3}{2}\right)^2=\left(\frac{2}{3}\right)^2$(x−12 )2+(y−32 )2=(23 )2
(a, b)=(12 , 32 ), r=​23

Answer 16

(a, b)=(1/2 , 3/2 )​, r=23

Answer 17

no its not 23 dear is 2/3