Question

Please help!

If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction becomes 1. Determine the original fraction.

Which of the following equations represents "If the numerator of a fraction is increased by 3, the fraction becomes 3/4"? (Hint: cross products)

3n + 9 = 4d
4n + 3 = 3d
4n + 12 = 3d

@mathmale

Answer 1

this problem statements translates into TWO different equations which must be solved simultaneously.

Let the fraction be n/d (numerator over denominator).

"Increase the numerator by 3 and find that the result equals 3/4"
See whether you can write one equation that reflects this. share your equation.

Answer 2

Would it be
n+ 3 = 3/4

Answer 3

@mathmale

Answer 4

@rubyyy

Answer 5

r u still there?

Answer 6

xx+7

if the numerator is increased by 3,
then
x+3x+7=34

by cross multiplication we get,
4 ( x +3) = 3 (x+7)
4x+12=3x+21
4x-3x=21-12
x=9

So the required fraction is 9 / 16

Answer 7

okay I think I get it. Thanks so much.

Answer 8

No prob :P