HELP!!!
@Agl202
@Michele_Laino
for lines to be perpendicular their GRADIENTS have to satisfy the equation gradient of line 1 * gradient of line 2 = -1 Now work it out.
Perpendicular: negative reciprocal slopes
i dont know what any of that means lol
Example: if the slope of 1 line 2, then the slope of the line perpendicular has to be \(-\dfrac{1}{2}\)
for lines to be perpendicular their GRADIENTS have to satisfy the equation gradient of line 1 * gradient of line 2 = -1 Now work it out. Do you get this?
no
okay do you know what are the gradients of the line given
I dont know what gradients are
the coefficients with x
is the answer A?
now dont just start guessing answers
do you understand what a gradient is a straight line equation
well half of 8 is 4 and you can add 4 to 1 and get 5 so A makes sense
Yeah the numbers with x
no A is not correct
let me just show why A is not correct Okay for A the equations are \[\large\rm y= 8x+5 \]\[\large\rm y= -8x+5 \] Since the gradient is the number with x the gradient in first line is 8 and the second line is -8. Now put them in the equation. \[\large\rm m_1*m_2=-1 \]\[\large\rm 8*-8=-1 \]\[\large\rm -64=-1 \] Since -64 doesnt equal to -1 these equations are not perpendicular.
Now work out the same reasoning for all the other equations and you will have your answer
im trying to figure these out as quick as possible because i dont have alot of time to do these
and i dont get it
practice makes perfect and practice do takes a hell of a time. And what part you dont get?
all of it
im timed and i am not gonna be able to finish
okay just apply this Gradient = - 1/gradient If the gradient of the first line is 8, then the other should be -1/8. If that doesn't happen they aren't perpendicular.
No nevermind its D.
correct is c
Wait C is right? how?
first line gradient 5, second line gradient -1/5
ohh.
thanks
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