Question

Another question

Answer 1

\[f(x) = \frac{ 1 }{ \sqrt{x+4} }\]

find

\[f'(2)\]

Answer 2

I'll show my work so far

Answer 3

having a little trouble simplifying this problem

Answer 4

@hartnn what I was asked to do was to use to find the derivative

\[\frac{ f(x+h)-f(x) }{ h }\]

Answer 5

ohhhhh

Answer 6

so f'(2) will be just
\(\frac{ f(2+h)-f(2) }{ h }\)

Answer 7

yeah, when I did this I got stuck at simplifying it. I was trying to show you where I got up to but my equation bar froze

Answer 8

use draw tool :3

Answer 9

\[\frac{ \frac{ 1 }{ \sqrt{x+4}+h } -\frac{ 1 }{ \sqrt{x+4} }}{ h }\]

Answer 10

\[f(x) = \frac{ 1 }{ \sqrt{x+4} }\]

Answer 11

supposed to find \[f'(2)\]

Answer 12

yeah so you can directly plug in x= 2 for ease of solving

Answer 13

oh wait,
your f(x+h) is not correct

Answer 14

After this part @hartnn I dont know how to simplify

\[\frac{ \frac{ 1 }{ \sqrt{x+4}+h } -\frac{ 1 }{ \sqrt{x+4} }}{ h }\]

\[\frac{ \frac{ 1 }{ \sqrt{6+h} } -\frac{ 1 }{ \sqrt{6} } }{ h }\]

Answer 15

oh yeah, now its correct.

Answer 16

ok yeah and what i'm not getting is how to simply this