Question

How would I go about taking the double derivative of the function F(x) = integral[1, 3x] ln(t^2)dt? The only problem I have is with the initial derivative.

Answer 1

\(\Large \dfrac{d}{dx}\int \limits_{a}^{g(x)}h(x)dx = h(g(x))g'(x)
\)

Answer 2

So F'(x) would be 3ln((3x)^2)?

Answer 3

yes!

Answer 4

you can simplify that further

Answer 5

3ln(9(x^2))?

Answer 6

\(\ln A^2 = 2 \ln A\)

Answer 7

6ln(3x)? or would it be 6ln(9x)?

Answer 8

Oh, 6ln(3x).

Answer 9

yes

Answer 10

Thank you so much for the help.

Answer 11

need help in finding its derivative?
whats the final answer you got? just for verification

Answer 12

6/x

Answer 13

\(\huge \checkmark \)

Answer 14

Thanks.

Answer 15

welcome ^_^