http://prntscr.com/a8s6h5 So, I understand all but one of the steps. Could someone explain why in step six the denominator's are RQ and SQ? Like, what property of equality makes step six make sense?
@jhonyy9 Can you help me with mine?
step 6 cam from step 4 with the substitutions made using step 5... you already know how step 4 came and how RQ and SQ are already the denominators, right?
Hm, I don't think I explained this properly. I know where the step came from. I want to know what property of equality justifies step six. For eg, why in step 6 did it go froom the equal sign (=) to the division sign XR+RQ/RQ and why did RQ and YQ replace XQ and YQ?
@imqwerty
@imqwerty HALP this poor fellow
@ganeshie8
Does step4 make sense to you ?
Yes. @ganeshie8
Do you see how XQ equals XR+RQ ?
Yes, What I don't understand is why after step 5 the equation went from XQ=XR+RQ and YQ=YS+SQ to a proportion equation where XR+RQ/RQ=YS+SQ/SQ. Where did that equation come from? How did that translation come from? @ganeshie8
Forget about step5 Stare at step4 and step6 a bit
they are taking the equation from step4 and replacing the numerators in step6
@ganeshie8 Explain step four to me then. Maybe I'm misunderstanding it.
How many triangles do you see in the given diagram ?
Two @ganeshie8
Are they similar ?
Yes @ganeshie8
So the corresponding sides form a proportion
XQ and RQ are corresponding sides YQ and SQ are corresponding sides
\[\dfrac{XQ}{RQ} = \dfrac{YQ}{SQ}\]
Alright. I understand so far. @ganeshie8
Take above equation and replace the numerators
replace \(XQ\) by \(XR+RQ\)
replace \(YQ\) by \(YS + SQ\)
What step is that? Also, I understand. @ganeshie8
Step6
Ah, alright. Can you explain the last step? @ganeshie8
Take step6 : \[\dfrac{XR+RQ}{RQ} = \dfrac{YS+SQ}{SQ}\]
distribute the denominator : \[\dfrac{XR}{RQ}+\dfrac{RQ}{RQ} = \dfrac{YS}{SQ}+\dfrac{SQ}{SQ}\]
\[\dfrac{XR}{RQ}+1 = \dfrac{YS}{SQ}+1\]
cancel 1 both sides and get \[\dfrac{XR}{RQ} = \dfrac{YS}{SQ}\] which is the last step
In your proof, they did not show all that simplification
THANK YOU @ganeshie8
Yw
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