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Mathematics 13 Online
OpenStudy (kikuo):

http://prntscr.com/a8s6h5 So, I understand all but one of the steps. Could someone explain why in step six the denominator's are RQ and SQ? Like, what property of equality makes step six make sense?

OpenStudy (kikuo):

@jhonyy9 Can you help me with mine?

hartnn (hartnn):

step 6 cam from step 4 with the substitutions made using step 5... you already know how step 4 came and how RQ and SQ are already the denominators, right?

OpenStudy (kikuo):

Hm, I don't think I explained this properly. I know where the step came from. I want to know what property of equality justifies step six. For eg, why in step 6 did it go froom the equal sign (=) to the division sign XR+RQ/RQ and why did RQ and YQ replace XQ and YQ?

OpenStudy (kikuo):

@imqwerty

ILovePuppiesLol (ilovepuppieslol):

@imqwerty HALP this poor fellow

OpenStudy (kikuo):

@ganeshie8

ganeshie8 (ganeshie8):

Does step4 make sense to you ?

OpenStudy (kikuo):

Yes. @ganeshie8

ganeshie8 (ganeshie8):

Do you see how XQ equals XR+RQ ?

OpenStudy (kikuo):

Yes, What I don't understand is why after step 5 the equation went from XQ=XR+RQ and YQ=YS+SQ to a proportion equation where XR+RQ/RQ=YS+SQ/SQ. Where did that equation come from? How did that translation come from? @ganeshie8

ganeshie8 (ganeshie8):

Forget about step5 Stare at step4 and step6 a bit

ganeshie8 (ganeshie8):

they are taking the equation from step4 and replacing the numerators in step6

OpenStudy (kikuo):

@ganeshie8 Explain step four to me then. Maybe I'm misunderstanding it.

ganeshie8 (ganeshie8):

How many triangles do you see in the given diagram ?

OpenStudy (kikuo):

Two @ganeshie8

ganeshie8 (ganeshie8):

Are they similar ?

OpenStudy (kikuo):

Yes @ganeshie8

ganeshie8 (ganeshie8):

So the corresponding sides form a proportion

ganeshie8 (ganeshie8):

XQ and RQ are corresponding sides YQ and SQ are corresponding sides

ganeshie8 (ganeshie8):

\[\dfrac{XQ}{RQ} = \dfrac{YQ}{SQ}\]

OpenStudy (kikuo):

Alright. I understand so far. @ganeshie8

ganeshie8 (ganeshie8):

Take above equation and replace the numerators

ganeshie8 (ganeshie8):

replace \(XQ\) by \(XR+RQ\)

ganeshie8 (ganeshie8):

replace \(YQ\) by \(YS + SQ\)

OpenStudy (kikuo):

What step is that? Also, I understand. @ganeshie8

ganeshie8 (ganeshie8):

Step6

OpenStudy (kikuo):

Ah, alright. Can you explain the last step? @ganeshie8

ganeshie8 (ganeshie8):

Take step6 : \[\dfrac{XR+RQ}{RQ} = \dfrac{YS+SQ}{SQ}\]

ganeshie8 (ganeshie8):

distribute the denominator : \[\dfrac{XR}{RQ}+\dfrac{RQ}{RQ} = \dfrac{YS}{SQ}+\dfrac{SQ}{SQ}\]

ganeshie8 (ganeshie8):

\[\dfrac{XR}{RQ}+1 = \dfrac{YS}{SQ}+1\]

ganeshie8 (ganeshie8):

cancel 1 both sides and get \[\dfrac{XR}{RQ} = \dfrac{YS}{SQ}\] which is the last step

ganeshie8 (ganeshie8):

In your proof, they did not show all that simplification

OpenStudy (kikuo):

THANK YOU @ganeshie8

ganeshie8 (ganeshie8):

Yw

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